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Old 30 Mar 2005, 10:03 PM   #1 (permalink)
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oxidation reduction problem important

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2H202 ----> 2H20 + 02

which species is the oxidising agent/ reducing agent and why ?

please help
thanx
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Old 30 Mar 2005, 10:04 PM   #2 (permalink)
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This is involving Oxidation Number.

Is this still in the syllabus?
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Old 30 Mar 2005, 10:07 PM   #3 (permalink)
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tip:
the oxidising agent/oxidant is what CAUSES something else to oxidise, it itself reduces
the reducing agent/reductant is what CAUSES somethign else to reduce, it itself oxidises
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Old 30 Mar 2005, 10:13 PM   #4 (permalink)
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therefore is 2H202 THE OXIDISING AGENT?
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Old 30 Mar 2005, 10:33 PM   #5 (permalink)
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in the conversion of h2o2 to 02 how many electrons are lost or gained by the two oxygen atoms
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Old 30 Mar 2005, 11:16 PM   #6 (permalink)
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Quote:
Originally Posted by clicker
2H202 ----> 2H20 + 02

which species is the oxidising agent/ reducing agent and why ?

please help
thanx
To identify a redox reaction, we investigate the oxidation states of the individual species involved.

In hydrogen peroxide, the oxidation state of oxygen is:
0 = (+1)(4) + (x)(4)
0 = +4 + 4
0 = 4 + 4x
-4 = 4x
-4/4 = x
-1 = x

therefore the oxidation state of oxygen in hydrogen perioxide is -1, and if we repeat the same process for the oxidation state of oxygen in water, find that its oxidation has changed to -2.
An decrease in oxidation state means that the species was reduced (to get from -1 to -2 it must gain an electron)
If oxygen was reduced, then it is the oxidising agent.
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Old 1 Apr 2005, 11:51 AM   #7 (permalink)
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Exactly! It involves using Oxidation Number.
Is this in the syllabus?
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Old 1 Apr 2005, 11:56 AM   #8 (permalink)
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i thought the oxidation number WAS in the syllabus?
we use it all the time...
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Old 1 Apr 2005, 11:57 AM   #9 (permalink)
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i thought the oxidation number WAS in the syllabus?
we use it all the time...
Yeah, it is.
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Old 1 Apr 2005, 11:58 AM   #10 (permalink)
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I'd assume it would be in the syllabus given the electrochem topic in the production of materials module. It's fairly easy to test and involves the application of a few simple rules in any case, so I can't see why you wouldn't be expected to know it.
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Old 1 Apr 2005, 11:59 AM   #11 (permalink)
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Old 1 Apr 2005, 12:03 PM   #12 (permalink)
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The concept is fairly straightforward.
Yes I know it.
Yes we've done it.
But, after we did it, our teacher said it wasn't specifically in the syllabus.
Possibly wrong.

Thanks guys
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