Sequence. (1 Viewer)

Fus Ro Dah

Member
Joined
Dec 16, 2011
Messages
248
Gender
Male
HSC
2013
Sorry, I made a typo. The first term should read T_{n+1}.
 

barbernator

Active Member
Joined
Sep 13, 2010
Messages
1,439
Gender
Male
HSC
2012
don't we need the value of T0 or something to evaluate T2012?
 

bleakarcher

Active Member
Joined
Jul 8, 2011
Messages
1,509
Gender
Male
HSC
2013
Don't we need some initial condition in order to find T_2012 like the value of T_0?
 

Fus Ro Dah

Member
Joined
Dec 16, 2011
Messages
248
Gender
Male
HSC
2013
My apologies, everybody. I am not thinking clearly at the moment. The initial value T_0 = T.
 

barbernator

Active Member
Joined
Sep 13, 2010
Messages
1,439
Gender
Male
HSC
2012
<a href="http://www.codecogs.com/eqnedit.php?latex=\frac{T}{1@plus;4044121T}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\frac{T}{1+4044121T}" title="\frac{T}{1+4044121T}" /></a> edited.

?
 
Last edited:

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
On second attempt, and this time not adding an extra 'T' which screwed me up before I get:



Where denotes the k'th triangular number.
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Falls apart from the substitution S_n=1/T_n.

In the case T=1 this yields: T_n= 2/(n^2-n+2).
 

RealiseNothing

what is that?It is Cowpea
Joined
Jul 10, 2011
Messages
4,591
Location
Sydney
Gender
Male
HSC
2013
Since triangular numbers can be worked out using we get:



Therefore:

 
Last edited:

deswa1

Well-Known Member
Joined
Jul 12, 2011
Messages
2,256
Gender
Male
HSC
2012
subbed in twice and observed pattern... lol. Is it correct?
Haha I do this for so many questions. Not sure if you're right- haven't looked at the question. I think this question is the only one out of the set of like 4 that Fus just posted that I'll have a chance at solving lol
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top