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Old 6 Nov 2009, 10:13 AM   #1 (permalink)
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A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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If any of you have done this practical then can you tell me what will happen if we carry out this investigation in an area of no sunlight. Will it make any difference to the reaction between the hydrocarbons and the bromine water.
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Old 6 Nov 2009, 10:24 AM   #2 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Cyclohexane requires UV light to react with Bromine water quicker.
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Old 6 Nov 2009, 10:36 AM   #3 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Yeah, it must be carried out in the dark because the cyclohexane will slowly react with UV light.

Cyclohexene --> Will go clear with or without UV light
Cyclohexane --> Will go clear slowly with UV light
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Old 7 Nov 2009, 12:44 PM   #4 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Alkenes are more reactive than alkanes due to the presence of their double bond. Alkenes go through what is called an addition reaction. It is where in an alkene; a double bond is broken and replaced with two new covalent bonds added across double bond where a foreign element/compound attaches itself. >>
>>
e.g. Ethene + Bromine --> 1, 2 – dibromoethane>>

> >

As mentioned above this is described as an addition reaction because extra elements are being added to the hydrocarbon and breaking the double bond. Alkanes go through a process called a substitution reaction. The substitution needs the presence of UV light to go through.


>>

>>When for example Ethane and Bromine undergo a substitution reaction the compound HBr is formed. This is due to one of the Br being substituted with an H on the hydrocarbon. Therefore Br2 is broken into two, one atom goes and joins the hydrocarbon and the H which the Br replaces attaches on to the free Br to make HBr. >>
> >
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Old 8 Nov 2009, 10:23 AM   #5 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Is there any particular reason why bromine water is used in this experiment?
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Old 8 Nov 2009, 6:28 PM   #6 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Hey can someone complete and balance this equation:

C6H12 +Br2 + H20----->?
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Old 8 Nov 2009, 7:40 PM   #7 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Bump
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Old 8 Nov 2009, 9:30 PM   #8 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Quote:
Originally Posted by Dragonmaster262 View Post
Is there any particular reason why bromine water is used in this experiment?
It is coloured.
When it reacts with the alkene it forms a colourless product. The change from coloured to colourless indicates that a reaction has occured.
Whereas if you were going to add water across the double bond, the mixture would start colourless and remain colourless. You cant be certain that anything has happened.
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Old 9 Nov 2009, 2:24 AM   #9 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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Originally Posted by bayan92 View Post
Alkenes are more reactive than alkanes due to the presence of their double bond. Alkenes go through what is called an addition reaction. It is where in an alkene; a double bond is broken and replaced with two new covalent bonds added across double bond where a foreign element/compound attaches itself. >>
>>
e.g. Ethene + Bromine --> 1, 2 – dibromoethane>>

> >

As mentioned above this is described as an addition reaction because extra elements are being added to the hydrocarbon and breaking the double bond. Alkanes go through a process called a substitution reaction. The substitution needs the presence of UV light to go through.


>>

>>When for example Ethane and Bromine undergo a substitution reaction the compound HBr is formed. This is due to one of the Br being substituted with an H on the hydrocarbon. Therefore Br2 is broken into two, one atom goes and joins the hydrocarbon and the H which the Br replaces attaches on to the free Br to make HBr. >>
> >
Copy pasted directly from Ahmad's Notes.
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Old 9 Nov 2009, 3:27 AM   #10 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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Originally Posted by Dragonmaster262 View Post
Hey can someone complete and balance this equation:

C6H12 +Br2 + H20----->?
Does anybody know how to do this?
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Old 9 Nov 2009, 10:13 AM   #11 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Quote:
Originally Posted by Dragonmaster262 View Post
Copy pasted directly from Ahmad's Notes.
No it isn't. My own practical report. Can be downloaded below.

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As for the equation involving water, I have never done it with water.
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Old 9 Nov 2009, 10:59 AM   #12 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

Quote:
Originally Posted by Dragonmaster262 View Post
Hey can someone complete and balance this equation:

C6H12 +Br2 + H20----->?
Water doesn't react in the equation, it's just the solvent.

C6H12 +Br2-----> Br2C6H10 + H2 --> All aqeous except for H2 which is a gas

If you draw it, the carbons are in a hexagon shape and the above reaction is just an addition reaction, where the 2 Br atoms takes the place of 2 H atoms.

Note that although cyclohexane would react with the bromine with UV light, it takes a very long time so you don't need to do the experiment in a dark room - cyclohexene would react very quickly so you just need to note which one decolourises the bromine water quickly.

Edit: Equation should be C6H12 + Br2 --> C6H12Br2 with all states being aqueous
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Last edited by annabackwards; 9 Nov 2009 at 4:53 PM.
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Old 9 Nov 2009, 3:58 PM   #13 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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Originally Posted by annabackwards View Post
Water doesn't react in the equation, it's just the solvent.

C6H12 +Br2-----> Br2C6H10 + H2 --> All aqeous except for H2 which is a gas

If you draw it, the carbons are in a hexagon shape and the above reaction is just an addition reaction, where the 2 Br atoms takes the place of 2 H atoms.

Note that although cyclohexane would react with the bromine with UV light, it takes a very long time so you don't need to do the experiment in a dark room - cyclohexene would react very quickly so you just need to note which one decolourises the bromine water quickly.
Youve drawn a substitution reaction. Your product is still an alkene.

Bromine + alkene is an addition reaction to form an alkane.

C6H12 + Br2 --> C6H12Br2

Although technically the reaction is:
Br2 + H2O --> HBr + HOBr
and both C6H12Br2 and C6H12BrOH are formed.
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Old 9 Nov 2009, 4:15 PM   #14 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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Originally Posted by brenton1987 View Post
Youve drawn a substitution reaction. Your product is still an alkene.

Bromine + alkene is an addition reaction to form an alkane.

C6H12 + Br2 --> C6H12Br2

Yeah brenton is right. Btw this whole UV stuff tbh is EXTRA knowledge. You actually don't want to talk about UV at all because then your not controlling your variables. The only thing you want to change is the functional group so alkanes/alkenes. The other thing is the aim of the experiment is to distinguish between the reactivities of the two so by exposing to UV light, you won't be able to do this.
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Old 9 Nov 2009, 4:52 PM   #15 (permalink)
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Re: A question about the effect of no sunlight on cycloalkanes and cycloalkenes

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Originally Posted by brenton1987 View Post
Youve drawn a substitution reaction. Your product is still an alkene.

Bromine + alkene is an addition reaction to form an alkane.

C6H12 + Br2 --> C6H12Br2

Although technically the reaction is:
Br2 + H2O --> HBr + HOBr
and both C6H12Br2 and C6H12BrOH are formed.
I stand corrected; it's been less than a week and i'm forgetting details... at least i remembered that it was an addition reaction XD

Yeah, double bond breaks open and Br2 adds across
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