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25 Sep 2009, 8:28 PM
| #1 (permalink) |
| Member HSC: 2010 Gender: Male Location: Melbourne, Australia
Join Date: Feb 2009
Posts: 165
Last Activity:
Today, 11:34 AM  | Need help with the following question... You can hide this advertisement by registering. Not sure how to approach this next question...I'm usually good at stoichiometry but this question has me stumped...What volume of water would have to be added to 0.500L of 10.0M potassium hydroxide to make them 1.00M? Please show me the steps needed to answer the question too. Thanks |
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25 Sep 2009, 8:35 PM
| #3 (permalink) |
| Member HSC: 2010 Gender: Male Location: Melbourne, Australia
Join Date: Feb 2009
Posts: 165
Last Activity:
Today, 11:34 AM | Re: Need help with the following question... See that's what I thought at first, but my answer just didn't match the answer at the back of the book (which is 4.5L) |
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25 Sep 2009, 9:01 PM
| #4 (permalink) | |
| Redfella  HSC: 2009 Gender: Male Location: North Bondi
Join Date: Mar 2008
Posts: 991
Last Activity:
Today, 1:46 AM | Re: Need help with the following question... c1v1 = c2v2 0.5 x 10 = 1 x v2 v2 = 5L You already have 0.5L, hence 4.5L needs to be added.
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25 Sep 2009, 9:03 PM
| #5 (permalink) | |
| Member HSC: 2010 Gender: Male Location: Melbourne, Australia
Join Date: Feb 2009
Posts: 165
Last Activity:
Today, 11:34 AM | Re: Need help with the following question... Quote:
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