Le Chatelier

yummy-cookies · 7 Oct 2009, 12:04 PM

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I was wondering if the result of changing the concentration of a gas in an equilbrium reaction involving gases would be affected by the mole ratio of the gases. Is an increase in concentration like an increase in pressure - the reaction favouring the side with less moles?

For example in N₂O_4(g) <--> 2NO_2(g) by increasing the concentration of N₂O₄ will the equilibrium shift to the right?

kwabon · 7 Oct 2009, 8:41 PM

Quote:

Originally Posted by yummy-cookies

I was wondering if the result of changing the concentration of a gas in an equilbrium reaction involving gases would be affected by the mole ratio of the gases. Is an increase in concentration like an increase in pressure - the reaction favouring the side with less moles?

For example in N₂O_4(g) <--> 2NO_2(g) by increasing the concentration of N₂O₄ will the equilibrium shift to the right?

yes will shift to the right.

and no for your initial question regarding whether increasing the concentration is related to the increasing the pressure.

just think of it this way, increasing the conc. of the left side (reactants) will shift the equilibrium to the right. and vice versa.
decreasing the conc. of the left side (reactants) will shift the equilibrium to the left.
both obviously due to le chateliers principle. and this is also regarding all equilibrium equations.

gurmies · 9 Oct 2009, 9:39 AM

Pressure is however, related to volume =] Inversely in fact.

hermand · 9 Oct 2009, 10:02 AM

Quote:

Originally Posted by yummy-cookies

I was wondering if the result of changing the concentration of a gas in an equilbrium reaction involving gases would be affected by the mole ratio of the gases. Is an increase in concentration like an increase in pressure - the reaction favouring the side with less moles?

For example in N₂O_4(g) <--> 2NO_2(g) by increasing the concentration of N₂O₄ will the equilibrium shift to the right?

i know what you're trying to say, but it's only like an increase in pressure if that gas is the only one present.

an overall increase in pressure of an only gaseous reaction will make no difference to the equilibrium.

study-freak · 10 Oct 2009, 2:06 PM

Quote:

Originally Posted by hermand

i know what you're trying to say, but it's only like an increase in pressure if that gas is the only one present.

an overall increase in pressure of an only gaseous reaction will make no difference to the equilibrium.

It depends on the mole ratio of gases in the reaction (unless I misunderstood it)

untouchablecuz · 10 Oct 2009, 2:10 PM

e.g. habor process

N₂_(g)+3H₂_(g)->2NH₃_(g)

1mol+3mol->2mol

4mol->2mol

if pressure increases (i.e. if the gases are compressed), then the equilibrium will move to the right because this favours the production of a smaller amount of particles (and vice versa)

study-freak · 10 Oct 2009, 2:13 PM

Quote:

Originally Posted by untouchablecuz

e.g. habor process

N₂+3H₂->2NH₃

1mol+3mol->2mol

4mol->2mol

if pressure increases (i.e. if the gases are compressed), then the equilibrium will move to the right because this favours the production of a smaller amount of gaseous particles (and vice versa)

Just added one word but anyway +1
In the HSC, don't forget to say "gaseous"
I'm pretty sure that it will affect your mark.

untouchablecuz · 10 Oct 2009, 2:15 PM

ah ok, thanks

hermand · 10 Oct 2009, 4:50 PM

Quote:

Originally Posted by study-freak

It depends on the mole ratio of gases in the reaction (unless I misunderstood it)

blehh. you're right.

far out i really should not have neglected chem.

7 Oct 2009, 12:04 PM	#1 (permalink)
yummy-cookies Member HSC: 2009 Gender: Female Join Date: Oct 2008 Posts: 143 Last Activity: 7 Nov 2009, 10:27 PM	Le Chatelier - changing concentrations and gases You can hide this advertisement by registering. I was wondering if the result of changing the concentration of a gas in an equilbrium reaction involving gases would be affected by the mole ratio of the gases. Is an increase in concentration like an increase in pressure - the reaction favouring the side with less moles? For example in N₂O_4(g) <--> 2NO_2(g) by increasing the concentration of N₂O₄ will the equilibrium shift to the right?

10 Oct 2009, 2:10 PM	#6 (permalink)
untouchablecuz Supreme Member HSC: 2009 Gender: Male Join Date: Mar 2008 Posts: 1,281 Last Activity: Today, 11:23 AM	Re: Le Chatelier - changing concentrations and gases e.g. habor process N₂_(g)+3H₂_(g)->2NH₃_(g) 1mol+3mol->2mol 4mol->2mol if pressure increases (i.e. if the gases are compressed), then the equilibrium will move to the right because this favours the production of a smaller amount of particles (and vice versa) __________________ My dear brothers, never forget, when you hear the progress of enlightenment vaunted, that the devil's best trick is to persuade you that he doesn't exist! Last edited by untouchablecuz; 10 Oct 2009 at 2:14 PM.

10 Oct 2009, 2:15 PM	#8 (permalink)
untouchablecuz Supreme Member HSC: 2009 Gender: Male Join Date: Mar 2008 Posts: 1,281 Last Activity: Today, 11:23 AM	Re: Le Chatelier - changing concentrations and gases ah ok, thanks __________________ My dear brothers, never forget, when you hear the progress of enlightenment vaunted, that the devil's best trick is to persuade you that he doesn't exist!

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