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Thread: Molar Ratio of Titration

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    Molar Ratio of Titration

    hey guys just having a little trouble understanding the molar ratio in titration calulations. like if the molar ratio of acid to base is 2:1 which one do i times by 2 when calculating number of moles. heres an e.g. questions:

    What is the concentration of H2SO4 if 29mL is required to neutralise 25.00mL of 0.2mol/L NaHCO3.

    the equation would be:

    H2SO4 + 2NaHCO3 ------> Na2SO4 + 2H2O + 2CO2

    so what do i do from here?
    thanks guys

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    Re: Molar Ratio of Titration

    1. Find n(NaHCO3) by using n=cv

    2. Find n(H2SO4) by dividing n(NaHCO3) by 2

    3. Find c(H2SO4) by using c=n/v

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    Re: Molar Ratio of Titration

    yeh so in this case by the equation;

    2 x number of moles of acid = number of moles of base
    (because in the balanced equation, the Na2Co3 has twice the number of moles)

    hence number of moles of acid = number of moles of base/2

    Then its just the normal calculations after to calculate conc. of acid using: C = n/v.

    Hope this helps

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