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| Senior Member HSC: 2008 Gender: Male
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7 Jul 2009, 2:37 PM ![]() | Acidic conditions and rusting You can hide this advertisement by registering. anode: Fe-->Fe2+ + 2e-cathode: 2h+ + 2e- ---> H2 0.00V overall Fe + 2h+ --> Fe2+ + H2 so the cathode equation here as its 0.00v means its going to go in preference of those with ve- reduction potentials. So if theses acidic conditions werent to be there i.e. no H+, what would the normal reduction reaction be? because i can see the one for rusting would be the o2 + 2h2O + 4e- --> 4OH- 0.4V im just wondering why if this is more likely to go why does the acidic 1 occur in the ocean thanks |
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| | #2 (permalink) |
| Senior Member HSC: 2008 Gender: Female
Join Date: May 2007
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18 Aug 2009, 9:09 PM ![]() | Re: Acidic conditions and rusting Acidic one occurs in the ocean for a few reasons. CO2 + H2O <-> H2CO3 According to Le Chatelier's principle, shifts to right as pressure is increased (ie as you go deeper). Also anaerobic bacteria (of the desulfivibrio family) produce H+ ions in the ocean. Hence the acidic one occurs in the ocean.
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