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Thread: Projectile motion question

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    Projectile motion question

    Hey! Could you guys help me with this problem? You don't have to answer all of the parts, just help me get started
    A ball is thrown horizontally from the top of a cliff and hits the ground 6 seconds later at 30 degrees to the vertical, moving at 67.9 m/s. Find:
    a) the initial velocity of the projectile
    b) initial horizontal and vertical velocity
    c) range
    e) final horizontal and vertical velocity

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    Re: Projectile motion question

    Some prep work I did before answering the questions:
    Uy = 0

    Vy = 67.9 cos 30
    = 58.80... m/s
    Vx = 67.9 sin 30
    = 33.95 m/s

    a) Uy = 0 (launched horizontally)
    Ux = Vx
    = 33.95 m/s

    Therefore initial velocity = 33.95 m/s horizontally (at 0 degrees to the horizontal)

    b) Initial horizontal velocity = 33.95 m/s
    Initial vertical velocity = 0 m/s

    c) Range = Ux*t
    = 33.95 * 6
    = 203.7 m

    e) All worked out already in prep work again:
    Final horizontal velocity = 33.95 m/s
    Final vertical velocity = 58.80... m/s (to 2 d.p)


    Hope that all makes sense. I am very prone to making careless mistakes too so let me know if one or more of my answers do not match your answers.
    2017 HSC: English Adv - Maths Ext 1 - Maths Ext 2 - Chemistry - Physics
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    Offering tutoring for 2U and 3U Maths around North Shore area, PM me for details.


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    Re: Projectile motion question

    Yep, your answers are spot on! Thank you so much for the help

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