Bored of Studies - View Single Post

brenton1987 · 12 Oct 2007, 9:17 PM

Iron (II) solution. (Nitrate).

MnO₄^- + 5 Fe²⁺ + 8 H⁺ --> Mn²⁺ + 5 Fe³⁺ + 4 H₂O

MnO₄^- is purple
Fe²⁺ is colourless
Mn²⁺ is colourless
Fe³⁺ is pale yellow

A change in solution colour from purple to pale yellow indicates that the permanganate has been reduced while the iron has been oxidised.

---

Iodide solution. (Sodium).

2 MnO₄^- + 10 I^- + 16 H⁺ --> 2 Mn²⁺ + 5 I₂ + 8 H₂O

MnO₄^- is purple
I^- is colourless
Mn²⁺ is colourless
I₂ is pale yellow

A change in solution colour from purple to pale yellow indicates that the permanganate has been reduced while the iodide has been oxidised.

---

Chloride Solution. (Sodium).

2 MnO₄^- + 10 Cl^- + 16 H⁺ --> 2 Mn²⁺ + 5 Cl₂ + 8 H₂O

MnO₄^- is purple
Cl^- is colourless
Mn²⁺ is colourless
Cl₂ is a noxious gas

A change in solution colour from purple to colourless indicates that the permanganate has been reduced while the chloride has been oxidised. Gas will also be present.

---

Methanoic Acid.

2 MnO₄^- + 6 H⁺ + 5 HCOOH --> 2 Mn²⁺ + 8 H₂O + 5 CO₂

MnO₄^- is purple
HCOOH^- is colourless
Mn²⁺ is colourless
CO₂ is a gas

A change in solution colour from purple to colourless indicates that the permanganate has been reduced while the methanoic acid has been oxidised. Gas will also be present.

---

Theres plenty more solutions out there. Just look at the table of reduction potentials to see what else permanganate can oxidise.
(Oxidation of Cu, Cu⁺, H₂C₂O₄, Au⁺, Pb, Mn, Ni, Sn, Sn²⁺, Zn)

12 Oct 2007, 9:17 PM	#4 (permalink)
brenton1987 Senior Member HSC: 2005 Gender: Male Location: Newcastle Join Date: Jun 2004 Posts: 252 Last Activity: Yesterday, 5:01 PM	Re: Experiment of KMnO4 Iron (II) solution. (Nitrate). MnO₄^- + 5 Fe²⁺ + 8 H⁺ --> Mn²⁺ + 5 Fe³⁺ + 4 H₂O MnO₄^- is purple Fe²⁺ is colourless Mn²⁺ is colourless Fe³⁺ is pale yellow A change in solution colour from purple to pale yellow indicates that the permanganate has been reduced while the iron has been oxidised. --- Iodide solution. (Sodium). 2 MnO₄^- + 10 I^- + 16 H⁺ --> 2 Mn²⁺ + 5 I₂ + 8 H₂O MnO₄^- is purple I^- is colourless Mn²⁺ is colourless I₂ is pale yellow A change in solution colour from purple to pale yellow indicates that the permanganate has been reduced while the iodide has been oxidised. --- Chloride Solution. (Sodium). 2 MnO₄^- + 10 Cl^- + 16 H⁺ --> 2 Mn²⁺ + 5 Cl₂ + 8 H₂O MnO₄^- is purple Cl^- is colourless Mn²⁺ is colourless Cl₂ is a noxious gas A change in solution colour from purple to colourless indicates that the permanganate has been reduced while the chloride has been oxidised. Gas will also be present. --- Methanoic Acid. 2 MnO₄^- + 6 H⁺ + 5 HCOOH --> 2 Mn²⁺ + 8 H₂O + 5 CO₂ MnO₄^- is purple HCOOH^- is colourless Mn²⁺ is colourless CO₂ is a gas A change in solution colour from purple to colourless indicates that the permanganate has been reduced while the methanoic acid has been oxidised. Gas will also be present. --- Theres plenty more solutions out there. Just look at the table of reduction potentials to see what else permanganate can oxidise. (Oxidation of Cu, Cu⁺, H₂C₂O₄, Au⁺, Pb, Mn, Ni, Sn, Sn²⁺, Zn)