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jumpthe · 10 Jun 2008, 4:26 PM

C1V1=C2V2

C1=10^(-13) from ph=-log(H3O+)
V1=1

C2= 10^(-12)
V2?

V2=0.1

therfore you must add 900ml

i think thats right, plz correct me anyone if im wrong

10 Jun 2008, 4:26 PM	#2 (permalink)
jumpthe Junior Member HSC: N/A Gender: Undisclosed Join Date: Mar 2008 Posts: 28 Last Activity: 18 Dec 2008, 8:32 PM	Re: ph acid/base question? C1V1=C2V2 C1=10^(-13) from ph=-log(H3O+) V1=1 C2= 10^(-12) V2? V2=0.1 therfore you must add 900ml i think thats right, plz correct me anyone if im wrong