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Originally Posted by riadnicolas How much water must be added to a 1 litre soln of a strong base of ph 13 in order to decrease the ph to 12?
I understand questions that ask to increase the ph but this one seemed new to me. |
10^-14 = [OH-] [H3O+]
-log[H3O+] = pH = 13
Therefore [H3O+] = 10^-13
For pH = 12, [H3O+] = 10^-12
Since you're increasing the the concentration of H3O+ ions by 10^1, i.e you multiply 10^-13 by 10 which gives you 10^-12, you are increasing the volume 10x.
So so add 9L to it. Sorry if I cant explain properly not very good witht the theory side of chem
:-S