question 2 (1 Viewer)

expertise123

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for question 2 v. which area did u have to shade and what was the equation of the line e.
 

bevstarrunner

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<img src="http://img44.exs.cx/img44/6114/2avgraph.jpg" alt="Image Hosted by ImageShack.us" />
including the line

line 'e' or l i think it was, was x=2
 

A2RAYA

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bevstarrunner said:
<img src="http://img44.exs.cx/img44/6114/2avgraph.jpg" alt="Image Hosted by ImageShack.us" />
including the line

line 'e' or l i think it was, was x=2
yeh it was x=2 for the equation..but wasnt the shaded area everything below the x axis only?...crap wat was i thinking then? :confused:

also wat were the coordinates of C...i know the x value was 2 cos of the lin l but wtf was the y vlue...i had no clue for sum reason, totally blanked out
 

Gobbie_7

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I got the co-ords of C to be (2,3). But just looking at the question, i think it is wrong.
 

bevstarrunner

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If u plug in any coordinate in the 'blue' section the inequality is satisfied

c was at (2,6)

You need to work out the equation of line AC, which is perpendicular to AB, so m=1.
then u go:
y - 3 = 1(x - (-1)
x - y + 4 = 0
then u plug in x = 2
2 - y - 4 = 0
y = 6
 
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