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Fortify · 12 Jun 2009, 8:29 PM

Co = 1.77g

O = 2.41g - 1.77g = 0.64g

n(Co) = m / mm = 1.77/58.93 = 0.030035635

n(Co) = 0.03

n(O) = 0.64/16 = 0.04

n(Co) = 0.04

Ratio is 0.03 : 0.04 = 3 : 4

Therefore Empirical Formula is Co3O4.

12 Jun 2009, 8:29 PM	#5 (permalink)
Fortify ♪웨딩드레스 HSC: 2009 Gender: Male Location: In a box under your bed . Join Date: Mar 2007 Posts: 1,251 Last Activity: Today, 9:15 PM	Re: Moles question Co = 1.77g O = 2.41g - 1.77g = 0.64g n(Co) = m / mm = 1.77/58.93 = 0.030035635 n(Co) = 0.03 n(O) = 0.64/16 = 0.04 n(Co) = 0.04 Ratio is 0.03 : 0.04 = 3 : 4 Therefore Empirical Formula is Co3O4. __________________