Quote:
Originally Posted by Fortify  Co = 1.77g
O = 2.41g - 1.77g = 0.64g
n(Co) = m / mm = 1.77/58.93 = 0.030035635
n(Co) = 0.03
n(O) = 0.64/16 = 0.04
n(Co) = 0.04
Ratio is 0.03 : 0.04 = 3 : 4
Therefore Empirical Formula is Co3O4. |
how did u get 58.93 as the molar mass of Cobalt, shoudnt it be 12.01+ 16?