Quote:
Originally Posted by Fluorescent  Last years and I have NFI... 
2008 , III, q1)a III
(iii) The number of bits in a memory location is referred to as wordlength. The table below shows how the word FISH would be stored with a 32- bit wordlength.
Address | Data
2E | 11000110 11001001 11100010 11001000
F I S H
Redraw the table showing how the word FISH would be stored with an 8-bit wordlength.
I HATE FISH QUESTIONS
HALP? |
Hmm the marking notes say:
Address Data
2E 11000110
2F 11001001
30 11100010
31 11001000
So i'm guessing, instead of storing all the information in one adress under 32 bits, it has distributed amongst 4 addresses using 8 bits each.
The address counting is in hexadecimal
Btw they have sample answers in the 2008 marking notes at the bottom near criteria.