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Thread: 2006 HSC Mathematics Solutions

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    Actuarial Co-op 06 T.Goodhew's Avatar
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    2006 HSC Mathematics Solutions

    Here are my worked solutions to the Mathematics (2Unit) HSC 2006. I apologise to those who downloaded the earlier versions, there were some minor calculation errors that have been fixed in the newer version of the solutions available here.

    Fixes:
    • The proof of Q6 a) iii. is now included as is Q7 which were accidentally left out.
    • Small trig evaluation errors made in evaluating sin of 2pi/3 were corrected.
    • The final two questions Q10 b) iv. and v. will be added shortly.
    Once again I sincerely apologise if you were worried because you downloaded a earlier solution file. You must excuse me I was working the solutions late between 11-12pm at night and small errors seem to be the consequence of that.

    Mathematics (2Unit) HSC Solutions - 2006 (v1.25)
    (Question 10 b) iv. v. will be included in v1.3)
    Last edited by T.Goodhew; 15 Aug 2007 at 6:05 AM.
    BCom (Actuarial Studies Co-op & Finance) @ UNSW

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    Re: 2006 HSC Mathematics Solutions

    oh these are so hot

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    Re: 2006 HSC Mathematics Solutions

    just a few mistakes but..but u did well. But you missed a whole question! 7 i think..

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    Actuarial Co-op 06 T.Goodhew's Avatar
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    Re: 2006 HSC Mathematics Solutions

    Oh , I did too... i have written the solutions to Q7... they will be included in this file and available to download by 12:30pm Today.

    if you could forward the mistakes you found to my email that would be apprecitated!!
    Last edited by T.Goodhew; 31 Oct 2006 at 11:51 AM.
    BCom (Actuarial Studies Co-op & Finance) @ UNSW

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    Re: 2006 HSC Mathematics Solutions

    Question 4a ii and iii are wrong.. use cosine rule instead... answer for bd should have been the square root of 27

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    Re: 2006 HSC Mathematics Solutions

    Isn't the sine rule question in q1 wrong too?

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    Re: 2006 HSC Mathematics Solutions

    gah how could you be bothered doing the whole paper for the second time? i never want to see maths again - except your solutions to see how i went! oh, and chemistry mole/equation work...

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    Re: 2006 HSC Mathematics Solutions

    don't worry - thought you were a current hsc student

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    Re: 2006 HSC Mathematics Solutions

    why doesn't it let me look at the solutions stupid comp

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    HSC IS EVIL sando's Avatar
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    Re: 2006 HSC Mathematics Solutions

    yeh its not working for me either.. wats the deal ?

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    Re: 2006 HSC Mathematics Solutions

    Question 3: c) (ii) you have 13/2, shouldnt it be 14/2?? as n=14?? or am i wrong

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    Angry Re: 2006 HSC Mathematics Solutions

    man this is the fastest dlz eva....

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    Is in A State Of Trance shinji's Avatar
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    Re: 2006 HSC Mathematics Solutions

    i have a lil discrepancy with 2)c)
    i got a far more complicated equation than that.
    i got the same gradient.

    but instead of doing x=0 and y=1,
    i used found out y via x-> y=cos2x
    which gave y= 1/2

    and then did y-y1=m(x-x1)
    which equaled
    y- 1/2 = -(sqrt3)[x- pi/6]
    2y - 1 = -x[sqrt3] + [[pi](sqrt3)]/6
    -> x[sqrt3] + 2y - 1 - (pi[sqrt3])/6 = 0



    welll that's just me .. . lol
    NSW UAI - 'o6 - 90.45
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    HSC IS EVIL sando's Avatar
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    Re: 2006 HSC Mathematics Solutions

    in 2 (c) ... shouldnt the y-value be ...... y = cos2 (pi/6) = 1/2

    im no maths expert.. but correct me if im wrong

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    HSC IS EVIL sando's Avatar
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    Re: 2006 HSC Mathematics Solutions

    yes.. i got same at Shinji.. and he is like boy genius lol

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    Actuarial Co-op 06 T.Goodhew's Avatar
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    Re: 2006 HSC Mathematics Solutions

    Quote Originally Posted by shinji
    i have a lil discrepancy with 2)c)
    i got a far more complicated equation than that.
    i got the same gradient.

    but instead of doing x=0 and y=1,
    i used found out y via x-> y=cos2x
    which gave y= 1/2

    and then did y-y1=m(x-x1)
    which equaled
    y- 1/2 = -(sqrt3)[x- pi/6]
    2y - 1 = -x[sqrt3] + [[pi](sqrt3)]/6
    -> x[sqrt3] + 2y - 1 - (pi[sqrt3])/6 = 0



    welll that's just me .. . lol
    y - 1/2 = -(sqrt3)[x - pi/6]
    2y -1 = -2(sqrt3)[x - pi/6]
    2y -1 = -2(sqrt3)x +([sqrt3]pi/3)
    2(sqrt3)x +2y -1 -(pi[sqrt3]/3) = 0

    i think you will find ... Changed the solutions accordingly grr.. stupid mistakes i made late at night.
    BCom (Actuarial Studies Co-op & Finance) @ UNSW

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    Is in A State Of Trance shinji's Avatar
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    Re: 2006 HSC Mathematics Solutions

    woops. mybad. lol
    a little misclculation error for me as well there. haha
    im pretty sure ididn't do it in the exam~ XD

    and ur welcome =D

    @sando: me? lil genius boy? i wish! haha
    NSW UAI - 'o6 - 90.45
    Undergraduate Course - 'o7 - Bachelor of Commerce - UNSW
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    Re: 2006 HSC Mathematics Solutions

    I've been trying to open these solutions all day but it just wont seem to work and i was wondering whether any1 had any suggestions?

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    Re: 2006 HSC Mathematics Solutions

    Quote Originally Posted by falbrav
    I've been trying to open these solutions all day but it just wont seem to work and i was wondering whether any1 had any suggestions?

    yeh i had probs as well. insted of opening jsut save it to ur pc. worked 4 me.

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    Actuarial Co-op 06 T.Goodhew's Avatar
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    Re: 2006 HSC Mathematics Solutions

    Quote Originally Posted by rolfey24
    yeh i had probs as well. insted of opening jsut save it to ur pc. worked 4 me.
    I've moved the file to a faster server, so you should be able to download the solutions easier now, thanks shinji for your help
    BCom (Actuarial Studies Co-op & Finance) @ UNSW

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    Senior Member Loz_metalhead's Avatar
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    Re: 2006 HSC Mathematics Solutions

    Cool. I think I got 90/120...im so happy about that:wave:
    3rd Year B Commerce @ UNSW (ACCT/FINS)

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    Proud Aurion TRD owner skyline's Avatar
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    Exclamation Re: 2006 HSC Mathematics Solutions

    where de hec u gettin cosine rule for dat qn from, u juz take the angle from 180 degrees and den dat gives u angle DBA hence angle B= angle A since base angles of isoceles r equal den for length of BD you use L=radius times the angle from angle B... duz any1 else agree, correct me if im wrong????:rofl:

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    Re: 2006 HSC Mathematics Solutions

    Thanx for putting up the solutions .. the answer for 10 b v) - the minimum area is 32(root)3 cm^2, but i don't remember part iv).

    Also with question one - ur calculator was in radians, so the angle in part d is wrong.. it should be 18 degrees (nearest degree) not 35 degrees.

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    Re: 2006 HSC Mathematics Solutions

    im pretty sure the vertex for Q9 a is (3, -1) hence the focus is (3, 2)

    cause its

    12y = x^2 - 6x - 3

    add 12 to both sides

    12y + 12 = x^2 - 6x + 9
    12(y+1) = (x-3)^2


    is it

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    Senior Member Loz_metalhead's Avatar
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    Re: 2006 HSC Mathematics Solutions

    That's what I got. There's another thread where people said they also got (3,2)
    3rd Year B Commerce @ UNSW (ACCT/FINS)

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