oh these are so hot
Here are my worked solutions to the Mathematics (2Unit) HSC 2006. I apologise to those who downloaded the earlier versions, there were some minor calculation errors that have been fixed in the newer version of the solutions available here.
Fixes:
Once again I sincerely apologise if you were worried because you downloaded a earlier solution file. You must excuse me I was working the solutions late between 11-12pm at night and small errors seem to be the consequence of that.
- The proof of Q6 a) iii. is now included as is Q7 which were accidentally left out.
- Small trig evaluation errors made in evaluating sin of 2pi/3 were corrected.
- The final two questions Q10 b) iv. and v. will be added shortly.
Mathematics (2Unit) HSC Solutions - 2006 (v1.25)
(Question 10 b) iv. v. will be included in v1.3)
Last edited by T.Goodhew; 15 Aug 2007 at 6:05 AM.
BCom (Actuarial Studies Co-op & Finance) @ UNSW
oh these are so hot
just a few mistakes but..but u did well. But you missed a whole question! 7 i think..
Oh , I did too... i have written the solutions to Q7... they will be included in this file and available to download by 12:30pm Today.
if you could forward the mistakes you found to my email that would be apprecitated!!
Last edited by T.Goodhew; 31 Oct 2006 at 11:51 AM.
BCom (Actuarial Studies Co-op & Finance) @ UNSW
Question 4a ii and iii are wrong.. use cosine rule instead... answer for bd should have been the square root of 27
Isn't the sine rule question in q1 wrong too?
gah how could you be bothered doing the whole paper for the second time? i never want to see maths again - except your solutions to see how i went! oh, and chemistry mole/equation work...
don't worry - thought you were a current hsc student
why doesn't it let me look at the solutions stupid comp
yeh its not working for me either.. wats the deal ?
Question 3: c) (ii) you have 13/2, shouldnt it be 14/2?? as n=14?? or am i wrong
man this is the fastest dlz eva....
i have a lil discrepancy with 2)c)
i got a far more complicated equation than that.
i got the same gradient.
but instead of doing x=0 and y=1,
i used found out y via x-> y=cos2x
which gave y= 1/2
and then did y-y1=m(x-x1)
which equaled
y- 1/2 = -(sqrt3)[x- pi/6]
2y - 1 = -x[sqrt3] + [[pi](sqrt3)]/6
-> x[sqrt3] + 2y - 1 - (pi[sqrt3])/6 = 0
welll that's just me .. . lol
in 2 (c) ... shouldnt the y-value be ...... y = cos2 (pi/6) = 1/2
im no maths expert.. but correct me if im wrong
yes.. i got same at Shinji.. and he is like boy genius lol
y - 1/2 = -(sqrt3)[x - pi/6]Originally Posted by shinji
2y -1 = -2(sqrt3)[x - pi/6]
2y -1 = -2(sqrt3)x +([sqrt3]pi/3)
2(sqrt3)x +2y -1 -(pi[sqrt3]/3) = 0
i think you will find ... Changed the solutions accordingly grr.. stupid mistakes i made late at night.
BCom (Actuarial Studies Co-op & Finance) @ UNSW
woops. mybad. lol
a little misclculation error for me as well there. haha
im pretty sure ididn't do it in the exam~ XD
and ur welcome =D
@sando: me? lil genius boy? i wish! haha
I've been trying to open these solutions all day but it just wont seem to work and i was wondering whether any1 had any suggestions?
Originally Posted by falbrav
yeh i had probs as well. insted of opening jsut save it to ur pc. worked 4 me.
I've moved the file to a faster server, so you should be able to download the solutions easier now, thanks shinji for your helpOriginally Posted by rolfey24
BCom (Actuarial Studies Co-op & Finance) @ UNSW
Cool. I think I got 90/120...im so happy about that:wave:
3rd Year B Commerce @ UNSW (ACCT/FINS)
where de hec u gettin cosine rule for dat qn from, u juz take the angle from 180 degrees and den dat gives u angle DBA hence angle B= angle A since base angles of isoceles r equal den for length of BD you use L=radius times the angle from angle B... duz any1 else agree, correct me if im wrong????:rofl:
Thanx for putting up the solutions .. the answer for 10 b v) - the minimum area is 32(root)3 cm^2, but i don't remember part iv).
Also with question one - ur calculator was in radians, so the angle in part d is wrong.. it should be 18 degrees (nearest degree) not 35 degrees.
im pretty sure the vertex for Q9 a is (3, -1) hence the focus is (3, 2)
cause its
12y = x^2 - 6x - 3
add 12 to both sides
12y + 12 = x^2 - 6x + 9
12(y+1) = (x-3)^2
is it
That's what I got. There's another thread where people said they also got (3,2)
3rd Year B Commerce @ UNSW (ACCT/FINS)
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