"The refractive index for glass is 1.50. A beam of light strikes an air-glass boundary at an angle of 40 degrees. What is the value of the ratio sin i/sin i for light passing though air into glass." N1 = 1 N2 = 1.50 i = 40 r = x Sin i / Sin r = N2 / n1 .'. sin40/sinr = 1.50/1 Sin r = sin40/1.50 Sin r = 0.4285... r = 25.37.. So the ratio would be Sin 40 -------- Sin 25.37 I think.
Thanks Gussy Booo for your help. I realise I didn't type down the full Q for the one you were confused about, sorry ! It was "The refractive index for glass is 1.50. A beam of light strikes an air-glass boundary at an angle of 40 degrees. What is the value of the ratio sin i/sin i for light passing though air into glass."
