Recent content by freestyler__54

and dont you forget it!

can you be any more pityful !?!? dude, its painfully obvious that youre a loser, if you werent, you wouldnt need to keep dropping your (oh so casual) braggings

3 words - rippin it up! i got somewhere between 90 and 97 my hand is so sore! especially writing my frickin numbers on all them pages!!!

so whats the go with a secondary key?

im still goin with 'the city of sydney'

with ya bro - i wasnt sure so i just wrote my prepared response and linked what the techniques told me about politics to understanding events, personalities and situations

yep! matthew franklin wrote one of my readings.. ever read educating rita? mine were carla and nick - the people next to me during the exam

isnt it just binomial prob!?!

well, its obviously a LAN but with topology, its not a star - no central hub / server etc... but i dont think its a ring either - with a ring, if one computer goes down, you cant get past it, with this one, you can, i reckon you could also call it a bus... thoughts?

does anybody else get this funny feeling that universities paid off whoever designed the ipt course to dumb it down so that they didnt have to revamp first year theory?

get the 50 exam tips

could be asked in the hsc? you have to have them dont you? just do a net search, look for steinbeck, ts eliot, etc...

well, why? i could see how it could be 0 or undefined, but why is it 1???

you idiots pt II !!! as for the 2nd problem, same strategy... ways 2 men... 4C2 x 5C1 = 30 ways 1 man... 4C1 x 5C2 = 40 therefore: ways(at least 1 guy, 1 chick) = 30 + 40 = 70 thats the answer, 70! you dont double it because order doesnt count!!! (2C2) the way of arranging 2...

you idiots!!! 5402? 540? WHAT THE HELL!!!! (original problem) firstly - there are 8 letters in 'equation' and youre making 3 letter words, therefore the total possibilities (not excluding anything) is total ways = 8P3 = 336 therefore anything over 336 is obviously wrong!!! it was a...