Recent content by Jinxd

I did a question like that in the trials for 2U. The question was later removed because there were 2 answers and I never found out whether I was right. BUT what I did was find the integral of the gradient function and sub in a known point to find the constant. I'll post later on cos I...

Nope, they didn't give a domain. I guess i don't need to do that much.

Ahhh, yes. Pt of Inflexion, but that would be 1 of the 3 points. How would you find the ones on the side? Btw, ty for all the replies

That's good to know, but what about 3U? Would they ask for the x-int? If so, I'd still need an answer.

y = 2x^3 - 9x^2 + 12 I've found the stationary pts to be: MAX (0,12) MIN (3,-15) BUT I don't know how to find the x-intercepts. Usually, I would make y=0 then solve the polynomial, but in this case, i can't factorise it. so, can someone help me find the x-intercepts? and tell me...