Recent content by williamwolfe

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    Finding the general solution (sin3x = sin2x)

    To get the general solution, use the sin(a + b) formular with sin(3x) = sin(2x + x), Then manipulate the terms on both sides until you get the golden ratio forumula: x^2 - x - 1 = 0, where x = 2 cosx. Fascinating result: cosx = 1/2 (1 + sqrt(5))/2 and cosx = 1/2 (1 - sqrt(5))/2) Another...
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