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EY opens today :)

I think most students would dw

haha

Don't they close on the 23rd of may or something for pwc?

Edit: 23rd June*

^ thank you so much for that helpful advice :)

^

Conics is 4U so you learn it in year 12



inb4 wrong paper :p

3U: Parametrics
4U: Conics and Curve Sketching

Just checking, how far back should awards go? Should we only include recent ones or the ones throughout our entire high school life? (Not sure how much the HR needs/want to know)

It's the same format at the 2U one

Some are already open I think

Solve:

\frac{4x^2}{(1-\sqrt{1+2x})^2} \leq 2x+9

I think you are missing a \frac{1}{2}

When you sub u=x^2 you divide by 2x which cancels one of the x"s and you are left with x^2, which becomes u

\begin{align*}I&=\int \frac{dx}{(x+2)\sqrt{x^2+4x-5}}\\u^2&=x^2+4x-5\\&=(x+2)^2-9\\u^2+9&=(x+2)^2\\dx&=u\frac{du}{x+2}\\I&=\int \frac{u\cdot du}{(x+2)^2u}\\&=\int...

\begin{align*}\int \frac{\sin2x}{(1+\sin^2x)^2}dx&=\int \frac{ 2\sin{x}\cos{x}}{(1+\sin^2x)^2}dx\\&=\int \frac{ d\left ( \sin^2{x} \right )}{(1+\sin^2x)^2}\\&=-\frac{1}{\left ( 1+\sin^2x\right...

ah, I did it without substitution by completing the square and converting to partial fractions. It should be able to be integated into inverse tans ?
dunno if it works lol
...

not sure if I'm on the right track, but does the answer happen to have a lot of \sqrt{24}?

oops that's right, I misread it

I take that back lol

Don't get too used to it :p Can barely answer the other 99% of sy's questions





Ah that's a much easier substitution, thanks :)

Not exactly, it depends on the relative gaps between internal rankings

\begin{align*}x&=\tan^4\theta\\dx&=4\tan^3\theta\sec^2\theta d\theta\\ \frac{1}{1+\sqrt{x}}&=\cos^2\theta\\\int {\frac{dx}{1+\sqrt{x}}}&=\int\cos^2\theta\cdot 4\tan^3\theta\sec^2\theta...

Evaluate

\int_{0}^{1}\frac{x^2+3x+2}{x^2-x+1}dx

http://shop.cottonon.com/shop/rubi/ is pretty decent

The graphs that you are expected to draw in exam conditions will mostly likely have reasonable scale, i.e. a question won't ask you to draw something with a y-intercept of (0,-947)

A good...