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Personally, I would have made the substitution x=u^2.

As a result, you get the integral of u*sqrt(1+u), which is straight-forward to evaluate, and the substitution back to x is quick.

\\ f(x) = \frac{\pi}{4} (1+x^2)

=)

(is this cheating)

Just deleted more posts than I should have. Keep it civil please =)

If this really is your perspective, then something is wrong, regardless of your degree.

With regards to this, I don't think teachers marking hard is an excuse for a dramatic drop in ranks because would they not be marking everybody harshly?

If your teacher was only marking YOU...

This is true if attendance counts towards your final mark.

However, for OP's course, attendance does not count towards the final mark.

(but doesn't mean you should skip tutorials!)

You're fine, the attendance only really matters if you're borderline failing.

Solve them simultaneously for the point of intersection.

I'm in, love this game. Through Steam?

I don't understand the need for Z. Your problem above is 2 dimensional, so why is there Z?

Hypothetical situation:

"My school normally has its Chemistry cohort averaging around 50%. However, my cohort this year has its estimated average to be around 75%. Therefore, my cohort is...

Although it is a part of Physics, we cannot place it there. The reason is because the Physics course (and all the science courses) are designed such that a person NOT even doing 2 Unit Mathematics...

It's a classic proof for the fact that the common Year 7-10 approximation of pi actually exceeds it.

As undesirable as that may be, it is (unfortunately) something required for the state.

The number of students able to complete large questions by themselves (with no lead-up) is very small in...

\\ $By using the Trapezoidal Rule, with four function values, on the curve $ y=\frac{1}{x} $ in the domain $ 1 \leq x \leq 2 $, approximate $ \ln 2 $ correct to three decimal places.$

\\ \frac{d}{dt} \left (2 \ln 4t \right )= 2 \times \frac{1}{4t} \times 4 = \frac{2}{t}

\ddot{x} = \frac{d}{dx} \left ( \frac{1}{2} v^2 \right )

Also, if you found your x(t) correctly, you should be able to differentiate that twice to get the acceleration in terms of time.

Actually, it has a lot to do with university mathematics and it most certainly does not lead to nowhere, because it introduces students to the concept of 'Projective Geometry'.
...

Whenever I teach resisted motion and explain the different terminology, the class always laughs whenever I mention 'retardation'.

Same with 'latus rectum'.

I knew somebody was going to say this.

There are infinitely many functions satisfying this condition?

If you had the ability to remove a topic from the Extension 2 Mathematics course, what topic would you remove?

What is your favourite word from the Extension 2 Mathematics course?

Geometric probability is straying quite a bit from Extension 2 without any prior intuition. Not many students fully grasp the concept of probability being the area under a curve.

Say they make g be a negative quantity.

Your Cartesian, assuming the particle is projected from the origin, would be

y=\frac{gx^2}{2V^2}\sec ^2 \theta + x \tan \theta

Although we know that g...