Type: Posts; User: bleakarcher
lost 1/2 a mark for that question coz instead of setting theta=2pi/3 (as the question asked) I set it equal to pi/3 lol. they won't be so merciful in the hsc.
It's designed to wing.
What was the pH question? Interested.
I agree, could have definitely split it up a bit. Thanks for the criticism.
Have you guys prepared essays for the modules? I still need to do this.
English, I'm not even sure if I'm going to be able to survive.
Sorry man. Say you have a galvanic cell with no salt bridge. Wouldn't you still have an instantaneous EMF (essentially a voltage) between the two cells until almost immediately this EMF is negated by...
Does anyone know CodeBlue's email?
Yeah, I need to read the question more carefully. Also, I get what you're saying man and I understand there would be no current but why would there be no voltage? Wouldn't there still be a EMF...
lol I just saw the white texts. Question though man, are those actual observations, besides the first one to do with voltage? Also, why exactly is there no voltage (I have an idea just want to know...
Yeah, that makes sense. I just assumed the first half-equation was preferential. Thanks man.
At the anode: Mg(s)->Mg^(2+)(aq)+2e
The electrons liberated through the oxidation of the magnesium electrode migrate to the cathode through the external wire where they reduce the Fe^(2+) ions in...
From the formed iron Fe(s)->Fe^(2+)(aq)+2e.
I showed it in my previous answer here:
Corrosion of iron
Oxidation half-equation: Fe(s)->Fe^(2+)(aq)+2e
I thought the iron came from the Fe^(2+)(aq)+2e->Fe(s).
I couldn't think of any other points so I just put down ones according to my option topic Shipwrecks and Corrosion lol.
a) The anode is the magnesium piece of metal and the cathode is the carbon (graphite) rod.
b) A salt bridge is required to complete the circuit in a galvanic cell and to maintain electrical...
New question: Why is polystyrene rigid?
Can someone mark my answer to this question: How did Einstein's theory of special relativity and his explanation of the photoelectric effect lead to the reconceptualisation of the model of light?
Will do, thanks.
Yeah true, you could have the hydride ion H- with an oxidation state of -1. So what do you recommend I say instead?
Haber process: N2(g)+3H2(g)->2NH3(g) delta(H)=-92 kJ/mol
Since nitrogen on the left hand side of the equation is in its elemental form its oxidation state is zero as is the oxidation state of...
Why do CFCs and HCFCs have low to no solubility in water?
Thing is though, by dividing by x at the bottom and bottom then applying x=sqrt(x^2) we are assuming that x>0. So we've restricted the integrand to x>0 I think.
I got ln[(x+(1/x))+sqrt[x^2+(1/x)^2] + C