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Thread: Why does a deposit form on the electrode of a half cell in a galvanic cell?

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    Why does a deposit form on the electrode of a half cell in a galvanic cell?

    Someone pls explain this

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    Re: Why does a deposit form on the electrode of a half cell in a galvanic cell?

    One of the reactions in galvanic cell is oxidisation, while the other reduction.

    So the two electrode are metals. One of them will become the anode, the other cathode

    So let’s jusf take copper and silver for example .

    The more reactive one becomes anode (copper) so the other electrode cathode (will be silver)

    Oxidation (anode): cu(s) —> cu^2+ + 2e^-

    Reduction (cathode) Ag^+(aq) +e^- —> Ag(s)

    So as you can see in question two silver metal forms that’s the deposit formation thingy you were asking for
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    Re: Why does a deposit form on the electrode of a half cell in a galvanic cell?

    And the silver deposit forms as extra mass on the silver electrode (cathode)?

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    Senior Member jazz519's Avatar
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    Re: Why does a deposit form on the electrode of a half cell in a galvanic cell?

    Quote Originally Posted by Raindrop78 View Post
    And the silver deposit forms as extra mass on the silver electrode (cathode)?
    Yep
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