Evaluate the integral of root (9-x^2)dx from 3 to -3.
And
If the area of a semi circle is 0.7709 find an approximate for Pi. The semi circle has equation y = root (1-x^2). I get 1.5418 which is clearly wrong as Pi is 3.14
Oh yes I meant y=3.
So is the integral from 3 to -3? And is it -2/3(9-x)^3/2 but when you sub x=3 and -3 the answer is zero
This is my solution. Can someone tell me where I am making a mistake. Cause the answer is 14.137 correct to 3 dp.
https://imgur.com/gallery/qLQ1s
It's 6b.
Thats because you have to use a different approach, either try to do it the very easy way and just try to work out the area of the semi-circle (since its a simple shape which has an easy area to work out since you know its radius as InterGrand was hinting) or you could use trigonometric substitution subbing in x=3sinthetr or x=3costhetr
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MX1/2U - ADV. ENGLISH - BIOLOGY - CHEMISTRY - BUSINESS STUDIES 2017
No
Okay thank you. I didn't think we could use the formula.
For the second question, unless im not thinking straight the radius would have to be approximately 1/root 2 for the given area (i.e. 0.7709) to be correct which isnt the case since the radius would have to be 1 according to the given equation so either you made a mistake in typing up the question or the given question is just completely wrong or im just being a complete idiot and missing something
MX1/2U - ADV. ENGLISH - BIOLOGY - CHEMISTRY - BUSINESS STUDIES 2017
No
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