is not a function. It is not correct to write it as one.
The function notation should only be used with functions.
Hi,
A bit confused with the use of the notation y=f(x). If we have the circle x^2+y^2=1, we can obviously rearrange and make y the subject which gives y=+-(1-x^2)^0.5. Is it wrong to write f(x)=+-(1-x^2)^0.5 since this is not a function hence we can't use f(x)?
If so, does that also mean whenever we are given f(x)=..., we can assume the given relation must be a function?
is not a function. It is not correct to write it as one.
The function notation should only be used with functions.
HSC 2018 - [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design and Development]
_{1}∫^{(3√3)} t^{2} dt cos(3π/9) = log(^{3}√e) | Integral t^{2} dt, From 1 to the cube root of 3. Times the cosine, of three pi over nine, Equals log of the cube root of e.
THere is an imaginary vertical line test to prove if a graph is a function or not
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