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Thread: Helppp PLS 2U MATH QUESTION

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    Helppp PLS 2U MATH QUESTION

    5. Find the equation of the straight line that contains the POI of 3x+2y-12=0 and 5x-y-7=0 and that:
    c) is perpendicular to the line y=5

    I can do it doing simultaneous equations but thats beta shit and takes to long
    How do i do it using k's
    3x + 2y - 12 + k(5x - y - 7) = 0
    (3+5k)x + (2-k)y + (-12-7k) = 0
    WTF DO I DO NOW

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    Re: Helppp PLS 2U MATH QUESTION

    Quote Originally Posted by pencilspanker View Post
    5. Find the equation of the straight line that contains the POI of 3x+2y-12=0 and 5x-y-7=0 and that:
    c) is perpendicular to the line y=5

    I can do it doing simultaneous equations but thats beta shit and takes to long
    How do i do it using k's
    3x + 2y - 12 + k(5x - y - 7) = 0
    (3+5k)x + (2-k)y + (-12-7k) = 0
    WTF DO I DO NOW
    The desired line has equation 3x + 2y - 12 + k(5x - y - 7) = 0 for some value of k. All you need to do is find what k is.

    Hint: To do this, note that the desired line should be of the form ''x = something'', because it should be perpendicular to y = 5,
    kawaiipotato likes this.

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    Re: Helppp PLS 2U MATH QUESTION

    Yeah i know the line has to be x = something because it has to be a straight line up. But im confused because with a straight line up the gradient is infinity so wtf do i do

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    Re: Helppp PLS 2U MATH QUESTION

    Quote Originally Posted by pencilspanker View Post
    Yeah i know the line has to be x = something because it has to be a straight line up. But im confused because with a straight line up the gradient is infinity so wtf do i do
    If the line is , then there is no (or more precisely, the co-efficient of is zero).

    How could you make your equation's co-efficient be zero?
    HSC 2018 - [English Adv.] • [Maths Ext. 1] • [Maths Ext. 2] • [Chemistry] • [Software Design and Development]

    1(3√3) t2 dt cos(3π/9) = log(3√e) | Integral t2 dt, From 1 to the cube root of 3. Times the cosine, of three pi over nine, Equals log of the cube root of e.

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    Re: Helppp PLS 2U MATH QUESTION

    Do you do (2-k) = 0??? therefore k = 2?
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    Re: Helppp PLS 2U MATH QUESTION

    someone plss a nibba got a math exam tmrw

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    Re: Helppp PLS 2U MATH QUESTION

    Quote Originally Posted by pencilspanker View Post
    someone plss a nibba got a math exam tmrw
    fan96 liked your answer, meaning it's correct.

    Here is a quick explanation. The line required only has an x-value since it's perpendicular to y=5. It also has to go through the point of intersection between the two lines mentioned in the question, so the first thing you need to think about is finding that point of intersection I(x,y) BUT since the y-value is irrelevant here (since the equation of our line is x='something'), we only need to find the x value;

    Two ways you can go about it ( which are essentially the same); either find a value of k such that y is eliminated which you have done correctly or eliminate y using the elimination method of simultaneous equations, which is basically the same as the first method.
    Last edited by KAIO7; 12 Jun 2018 at 12:28 AM.
    pencilspanker likes this.
    Bsc (Advanced Mathematics)/(Neuroscience)/ TSP

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    Re: Helppp PLS 2U MATH QUESTION

    Thank u so much ur amazing
    KAIO7 likes this.

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