# Thread: Helppp PLS 2U MATH QUESTION

1. ## Helppp PLS 2U MATH QUESTION

5. Find the equation of the straight line that contains the POI of 3x+2y-12=0 and 5x-y-7=0 and that:
c) is perpendicular to the line y=5

I can do it doing simultaneous equations but thats beta shit and takes to long
How do i do it using k's
3x + 2y - 12 + k(5x - y - 7) = 0
(3+5k)x + (2-k)y + (-12-7k) = 0
WTF DO I DO NOW  Reply With Quote

2. ## Re: Helppp PLS 2U MATH QUESTION Originally Posted by pencilspanker 5. Find the equation of the straight line that contains the POI of 3x+2y-12=0 and 5x-y-7=0 and that:
c) is perpendicular to the line y=5

I can do it doing simultaneous equations but thats beta shit and takes to long
How do i do it using k's
3x + 2y - 12 + k(5x - y - 7) = 0
(3+5k)x + (2-k)y + (-12-7k) = 0
WTF DO I DO NOW
The desired line has equation 3x + 2y - 12 + k(5x - y - 7) = 0 for some value of k. All you need to do is find what k is.

Hint: To do this, note that the desired line should be of the form ''x = something'', because it should be perpendicular to y = 5,  Reply With Quote

3. ## Re: Helppp PLS 2U MATH QUESTION

Yeah i know the line has to be x = something because it has to be a straight line up. But im confused because with a straight line up the gradient is infinity so wtf do i do  Reply With Quote

4. ## Re: Helppp PLS 2U MATH QUESTION Originally Posted by pencilspanker Yeah i know the line has to be x = something because it has to be a straight line up. But im confused because with a straight line up the gradient is infinity so wtf do i do
If the line is , then there is no (or more precisely, the co-efficient of is zero).

How could you make your equation's co-efficient be zero?  Reply With Quote

5. ## Re: Helppp PLS 2U MATH QUESTION

Do you do (2-k) = 0??? therefore k = 2?  Reply With Quote

6. ## Re: Helppp PLS 2U MATH QUESTION

someone plss a nibba got a math exam tmrw  Reply With Quote

7. ## Re: Helppp PLS 2U MATH QUESTION Originally Posted by pencilspanker someone plss a nibba got a math exam tmrw
fan96 liked your answer, meaning it's correct.

Here is a quick explanation. The line required only has an x-value since it's perpendicular to y=5. It also has to go through the point of intersection between the two lines mentioned in the question, so the first thing you need to think about is finding that point of intersection I(x,y) BUT since the y-value is irrelevant here (since the equation of our line is x='something'), we only need to find the x value;

Two ways you can go about it ( which are essentially the same); either find a value of k such that y is eliminated which you have done correctly or eliminate y using the elimination method of simultaneous equations, which is basically the same as the first method.  Reply With Quote

8. ## Re: Helppp PLS 2U MATH QUESTION

Thank u so much ur amazing  Reply With Quote

#### Thread Information

##### Users Browsing this Thread

There are currently 1 users browsing this thread. (0 members and 1 guests)

#### Posting Permissions

• You may not post new threads
• You may not post replies
• You may not post attachments
• You may not edit your posts
•