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Thread: HSC 2012 Marathon :)

  1. #401
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    why doesn't the general formula work to integrate

    integral e^ln(x) = e^f(x)/f'(x) = e^ln(x)/1/x = x^2 =/= x^2/2

    i know that it can just be simplified to x, but im wondering why the formula doesn't work
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  2. #402
    Junior Member Kingportable's Avatar
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    Re: HSC 2012 Marathon :)

    Any ideas though?

  3. #403
    Sequential Timske's Avatar
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    Re: HSC 2012 Marathon :)

    isnt it f'(x)/f(x) ?
    B ECO@USYD 2013

  4. #404
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by nightweaver066 View Post
    lol
    did i just make an extremely rookie error?
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  5. #405
    Sequential Timske's Avatar
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    Re: HSC 2012 Marathon :)

    integral e^lnx = f'(x)/f(x) = 1/x

    woops
    B ECO@USYD 2013

  6. #406
    Executive Member bleakarcher's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Timske View Post
    integral e^lnx = f'(x)/f(x) = 1/x

    woops
    shitballs

    I just got on the forums again and I see this..

  7. #407
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Timske View Post
    integral e^lnx = f'(x)/f(x) = 1/x

    woops
    ok now u guys can lol at me, does that give me permission to lol at this?
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  8. #408
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    why doesn't the general formula work to integrate

    integral e^ln(x) = e^f(x)/f'(x) = e^ln(x)/1/x = x^2 =/= x^2/2

    i know that it can just be simplified to x, but im wondering why the formula doesn't work
    but 4srs, i know that e^ln(x)=x. but why can u not use e^f(x)/f'(x) to integrate instead. Is it something to do with the domain of the function?
    Last edited by barbernator; 17 Jun 2012 at 10:19 PM.
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  9. #409
    Moderator Carrotsticks's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by deswa1 View Post
    Oooh, if you could find it, can you post it again. A nice question that I remember you posting was how to integrate 1/1+tan^n(x) between 0 and pi/2 but that needs 4U techniques...
    I don't remember that question... Anyway here it is:

    Bachelor of Science (Adv. Mathematics) - University of Sydney:

  10. #410
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    LOL comments removed deswa and nightweaver hehe
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  11. #411
    Sequential Timske's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    but 4srs, i know that e^ln(x)=x. but why can u not use e^f(x)/f'(x) to integrate instead.
    because e^lnx = x thats why hahah
    B ECO@USYD 2013

  12. #412
    Junior Member Kingportable's Avatar
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    Re: HSC 2012 Marathon :)

    John Fitzpatrick 3U Mathematics 25(c) Question 3

    A particle movies in a straight line. At time t seconds, its displacement x cm from a fixed poin O in the line is given by x=5sin((pi/2)T + pi/6). Express the acceleration in terms of x only and hence show that the motion is simple harmonic. Find:

    iii) The speed when x=-2+1/2
    iv) the acceleration when x = -2 + 1/2

  13. #413
    Sequential Timske's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Kingportable View Post
    John Fitzpatrick 3U Mathematics 25(c) Question 3

    A particle movies in a straight line. At time t seconds, its displacement x cm from a fixed poin O in the line is given by x=5sin((pi/2)T + pi/6). Express the acceleration in terms of x only and hence show that the motion is simple harmonic. Find:

    iii) The speed when x=-2+1/2
    iv) the acceleration when x = -2 + 1/2
    x=-2+1/2 do you mean -2.5?
    B ECO@USYD 2013

  14. #414
    Exalted Member deswa1's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    LOL comments removed deswa and nightweaver hehe
    Ahh you noticed. I removed it because I didn't read your question properly and I didn't want to look like a retard if I was wrong. What is your question?

  15. #415
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by deswa1 View Post
    Ahh you noticed. I removed it because I didn't read your question properly and I didn't want to look like a retard if I was wrong. What is your question?
    the question is, why when integrating e^ln(x) through both methods e^f(x)/f'(x) and x yield different results?
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  16. #416
    Exalted Member deswa1's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    the question is, why when integrating e^ln(x) through both methods e^f(x)/f'(x) and x yield different results?
    How can you integrate e^ln(x) using this. If f(x)=ln(x), then f'(x)=1/x. Therefore to use this form, you would have to be integrating (1/x)(e^ln(x)) not just e^ln(x)

  17. #417
    Moderator Carrotsticks's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    the question is, why when integrating e^ln(x) through both methods e^f(x)/f'(x) and x yield different results?
    How did you get the bolded part? That is only applicable if f'(x) is a constant...
    Bachelor of Science (Adv. Mathematics) - University of Sydney:

  18. #418
    Junior Member Kingportable's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Timske View Post
    x=-2+1/2 do you mean -2.5?
    yes, btw i tried using x''=-n^2 . x and v^2=n^2 . (a^2 + x^2)

    My problem with differentiation from the displacement was that i didn't have a value for t

  19. #419
    Executive Member nightweaver066's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by deswa1 View Post
    Ahh you noticed. I removed it because I didn't read your question properly and I didn't want to look like a retard if I was wrong. What is your question?
    Same, then i realised his question is troll.

    B. Actuarial Studies / Science (Advanced Maths) @ UNSW '18

    HSC 2012 - 99.70:
    Advanced English, 3U Mathematics, 4U Mathematics, Chemistry, Physics

  20. #420
    Executive Member nightweaver066's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Carrotsticks View Post
    I don't remember that question...
    The question that you got from one of your students; that i indirectly sent you :P

    B. Actuarial Studies / Science (Advanced Maths) @ UNSW '18

    HSC 2012 - 99.70:
    Advanced English, 3U Mathematics, 4U Mathematics, Chemistry, Physics

  21. #421
    Moderator Carrotsticks's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by nightweaver066 View Post
    The question that you got from one of your students; that i indirectly sent you :P
    Oh right yes yes I remember now.

    Here's an interesting question:

    A and B are two positive integers such that A > B and A =/= B.

    Now consider A^B and B^A.

    Which one is larger? Do any conditions need to be imposed to satisfy each inequality?
    Bachelor of Science (Adv. Mathematics) - University of Sydney:

  22. #422
    Executive Member barbernator's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by nightweaver066 View Post
    Same, then i realised his question is troll.
    nah it wasn't a troll, i have just had my definition of integration wrong the whole time for exponents lol. its only e^f(x)/f'(x) for linear factors.... my bad
    Quote Originally Posted by Sy123 View Post
    Probably some time summer holidays (probably late summer) (dont quote me on this)

  23. #423
    Exalted Member deswa1's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by Carrotsticks View Post
    Oh right yes yes I remember now.

    Here's an interesting question:

    A and B are two positive integers such that A > B and A =/= B.

    Now consider A^B and B^A.

    Which one is larger? Do any conditions need to be imposed to satisfy each inequality?
    Consider A=5, B=2, B^A>A^B. Now consider A=3, B=2, A^B>B^A. Therefore conditions must be placed to satisfy the inequalities. Unfortunately I don't have time now to work it out- I'll try it tomorrow though because it looks cool

  24. #424
    Junior Member Kingportable's Avatar
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    Re: HSC 2012 Marathon :)

    Lol plox someone help me solve this question, its driving me crazy!

    John Fitzpatrick 3U Mathematics 25(c) Question 3

    A particle movies in a straight line. At time t seconds, its displacement x cm from a fixed poin O in the line is given by x=5sin((pi/2)T + pi/6). Express the acceleration in terms of x only and hence show that the motion is simple harmonic. Find:

    iii) The speed when x=-2 1/2 or x = - 5/2
    iv) the acceleration when x = -2 1/2 or x = - 5/2

  25. #425
    Executive Member nightweaver066's Avatar
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    Re: HSC 2012 Marathon :)

    Quote Originally Posted by barbernator View Post
    nah it wasn't a troll, i have just had my definition of integration wrong the whole time for exponents lol. its only e^f(x)/f'(x) for linear factors.... my bad
    Oh.. Sorry about that then.

    I wouldn't use that formula, stick to the simple and stick to 'balancing' to integrate.

    B. Actuarial Studies / Science (Advanced Maths) @ UNSW '18

    HSC 2012 - 99.70:
    Advanced English, 3U Mathematics, 4U Mathematics, Chemistry, Physics

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