Reply With Quoteis the answer 3 ?/
When a polynomial is divided by (x-3)(2x+1), the remainder is (3x-1)
Find the remainder when P(x) is divided by (2x+1)
does anyone know how to solve this?
I tried p(-1/2) = 0 + 3*(-1/2) -1 = -5/2 but that's not the right answer
Last edited by jxballistic; 8 Sep 2012 at 7:08 PM.
is the answer 3 ?/
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its 1/2Originally Posted by Timothy6340
Are you sure?
&=(x-3)(2x+1)Q(x)+3x-1 $ by the division transformation $\\ &=(2x+1)S(x) +a $ for some polynomials $ S(x) $ and $ Q(x),$ and a constant $ a.\\ \therefore (x-3)(2x+1)Q(x)+3x-1=(2x+1)S(x)+a\\ $Setting $ x =-\frac{1}{2} $ yields $\\ 3(-\frac{1}{2})-1=a\\ \therefore a=-\frac{5}{2})
Last edited by asianese; 9 Sep 2012 at 12:43 AM.
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I also get the remainder as -5/2. Could just be a mistake in the answers
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