Sequence induction proof (1 Viewer)

Drongoski

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In outline as LaTeXing is so tedious.



Therefore true for k = 1. Now assume true for n = k (k >= 1)



i.e. if true for n=k true also for n=k+1

. . . blah ... blah ... blah . . .
 
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MoonMonster196884

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it's very easy i did it.
Assume $b_{k}=1+\sum_{r=1}^{k-1}b_{r}^{2}$
RTP that for k+1
We know $b_{k+1}=b_{k}\left(b_{k}+1\right)$
=$b_{k}^{2}+b_{k}=b_{k}^{2}+1+\sum_{r=1}^{k-1}b_{r}^{2}$ by assumption
=what we were RTP
 

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