Inverse Trig. Question (1 Viewer)

[acevipa]

I'm having trouble with this question from fitzpatrick:

Prove that:

tan^-1 (4) - tan^-1 (0.6) = 45 degrees

 

[gurmies]

 

[addikaye03]

I'm having trouble with this question from fitzpatrick:

Prove that:

tan^-1 (4) - tan^-1 (0.6) = 45 degrees

[Finding the tan function of both sides]

tan(tan^-1(4)-tan^-1(0.6))=tan45

LHS=(4-0.6/1+4(0.6))
=(3.4/3.4)=1

RHS=1

therefore LHS=RHS

 

[gurmies]

[Times both sides by tan]

tan(tan^-1(4)-tan^-1(0.6))=tan45

LHS=(4-0.6/1+4(0.6))
=(3.4/3.4)=1

RHS=1

therefore LHS=RHS

Lol, it's not really a multiplication by tan, it's taking the tan of both sides xD

 

[addikaye03]

Lol, it's not really a multiplication by tan, it's taking the tan of both sides xD

hahaha yer, i knew someone would pull me up on that lol i cbb changing it...ok ok i will haha XD

 

[gurmies]

hahaha yer, i knew someone would pull me up on that lol i cbb changing it...ok ok i will haha xd

<3