Recent content by spice girl

i think this question was from the 2002 HSC (Q4?). simson's line.

if u haven't already noticed, i'm always on the right hand side of every equation :p

no turtle prolly jus needs to know when we need to vacate the clancy

hmm last time i checked, beryllium was less active than calcium.

go get a tutor if u want a better use for your time. time is money

no you're not ignorant; it hasn't been answered yet anions also absorb / emit energy. the difference is that the cations emit energies corresponding to the visible-light part of the EMR spectrum, whilst anions emit energies corresponding to higher (perhaps UV) part of the spectrum and thus...

multiply top and bottom by 1 + tan(x/2). i jumped a step and expanded the denominator already.

tan(45 + x/2) = [1 + tan(x/2)] / [1 - tan(x/2)] = [1 + tan(x/2)] ^2 / 1 - tan^2(x/2) = [1 + 2tan(x/2) + tan^2(x/2)] / 1 - tan^2(x/2) = * let t = tan(x/2) then * = 1 + 2t + t^2 / 1 - t^2 from t-results, we know that 2t/1 - t^2 = tanx, and 1 + t^2 / 1 - t^2 = 1/cosx = secx so tan(45 +...

geez unless they ask for a quantitative analysis, i reckon you can get away with using the keywords "high" and "low", in describing solubility.

i've recently discovered where the store of calcium carbide is in our school muhuahaha

but won't the Na+ ions left behind make the muffin basic? the only anions that could possibly be left behind is the hydroxide ion.

next time u pick up beakers when there are beakers with strong acid around: get a paper towel and wipe it dry. a poorly-documented laboratory test for conc acid is it discolours the paper. conc sulf turns the paper black, conc nitric turns it brown.

like, real solid stuff like calculations, etc. not arty-farty environmental and social issues with batteries and crap we get for HSC

you've diluted the acid when you added the silver nitrate in. that's why [H+] is decreased and hence pH rises

oh yea.... oops gee my maths is so crap now i can't count to 3 stoopid med it's brainwashing me