Im sure there are others in a similar boat...
Well here is the story...
I got a UAI of 96.75 and had my first few preferences as Engineering Space courses at Sydney Uni. After more thought i decided i did not want to do these but instead do Engineering/Architecture at Sydney Uni which ended up...
got the question in fron of me.
It is an exothermic reaction ( enthalpy is negative ).
increasing the temperature causes it to shift left towards the reactant. Therefore c) is not correct, d) is the answer.............
it is asking what will make it shift to the right.......
What did people get..
20mL of 0.008 Mol/L HCl is mixed with 30 mL of 0.05 Mol/L NaOH.
What is the resultant PH.
how i did it--->
n(H+ in HCl)= 0.02 x 0.08 = 1.6x10^-3
n(OH- in NaOH)= 0.03 x 0.05 = 1.5x10^-3
1.6x10^-3 - 1.5x10^-3 = 0.1x10^-3 (H+ ions left...
does any 1 think they will take sig-figs into account for any of the questions, i used them for all of them accept the ones about fuels. Thought it was stupid to do 3 sig figs on like a 10 digit number
ooh that was the only question i wasn't sure about. I used the Cl2 gas porential, times it buy 2 and added it to the +ve nickel one. That meant i got a voltage of about 2.9X volts, dont quite remember. What did evry 1 else get?
I talked about CAT scans, compared them to normal non tomographical xrays and showsed how tomography made it much better. Talked about MRI and PET scans and how without tomography the data would be useless.
lol im such a cyber bully.
At the time i made this you had not yet updated urs to the correct answers, so i thought it would be useful for people to have all the answers clearly defined without needing to read 3 pages of your thread.
btw i actually posted this list in another thread before you...
The question is asking about charged particles, proving they had momentum does not proved they are charged particles but rather normal particles. Initially they were thought to be non-charged particles as you said, and it was not untill JJ Thompson successfully deflected them with an electric...
-Explanation for 4-
I used the maths method
h=0.5 times 9.8 times t^2
it is therefore an arc of a parabola, as shown it c).
You do however want H to be on the x axis as this is the independent variable. This means it is t=0.5 times 9.8 times h^2.
This is the inverse of c) and is...
These are the real confirmed answers. All of them are correct accept 15 which is questionable.
*There is much debate over question 15, whether it is B or D. From the poll most people put B, but this is not...