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ii ) I will use algebraic method in approaching this question 1. you can make two equations y = tx + t y^2 + x^2 = 1 Hence solving simultaneously x = (1-t^2)/(1+t^2) hence subing this to linear equation y = (2t/(1+t^2)) iii) hence tan (A) = y/x = (2t/(1-t^2)) iv) using circle...

2 i) with this question draw a diagram to assist you in understanding the question Note that the line should intersect the circle in the FIRST QUANDRANT ie maximum t = when P lies on (0,1) hence 0 < t < 1 (greater or equal sign)

Q1 (a+b)^n + (a-b)^n note that their is (-) sign hence if you put them in general form you should see that every second tern ie for r= odd, the term cancels each other. Whereas for r= even ,they add up Hence = 2 (C0 a^n + C2 a^(n-2)b^2 + C4 a^(n-4) b^4 + ..... ) the last tern depends on...

2) note that 5^3 = 125 5^2 = 25 hence log(125) + log(25) + log(5) = 6log 5

Trials...

General solution. You can refer to your 3u textbook Youknow about A S T C right?? First if cos(x) =cos a For example cos x = .5 = cos60 Hence x= 60, 360-60, 360+ 60, 360 + (360-60),.... Hence similarly x = a, 360-a, 360+a, 720-a ... X= 2pi*k +or - a

Go through hsc papers in coroneos and see the worked out solutions. Then try similar questions until you master each type of the graphs :)

Ummm I did say that it didn't work following on what I had said However so there is no solution?

oh wait you gotta to take in fact that not all 3 solutions satisfy the equation shit... i dunno anyone

roots are integers, let the roots be (a,b,c,d) since a*b*c*d = 1 hence roots are 1,1,1,1 or -1-1,1,1 or -1,-1,-1,-1 -k = 1+1+1+1, -1+-1+1+1 or -1+-1+-1+-1 hence k = +4,-4 or 0?

whats the answer? i ve got +4, -4 or 0 i am not sure though

nope unless there was a specific question asking you to draw one,

OH... i did not see that.. in that case i think you re right 56 it is.:)

the working is : firstly you have to know that any number is divisble by 3 if all digits sum to be divisble by 3 ie (12132) is divisble by 3 because 1+2+1+3+2 = 9 divisble by 3. Now by T AND E for 4 digit values (3,1,8,9) , and (3,5,1,9) their sums are divisble by 3 the numbers are less...

really? i ve got 50 anyone?

4unit = 30% of talent + 70% of dedication Doable as long as you consistently dedicate your time on maths

If you work as an electrical engineering for long time and become like lets say designe or principle engineer what task would i be doing? Do you do a lot of difficult maths as an electrical engineer after uni?

Cheers brent :)

I was thinking about doing medicine, but i want to have some flexibility in my life, i don't want to work 70hours a week medicine is a good career but engineering suits me more i think

which university is better for engineering degree - University of Melbourne or UNSW? based on aspects of- salary, social life, cost of living, internation opportunity, faculty standards, etc (i know that UoM offers better accreditations after the master course: Eurace, Engineer Australia...