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Think about the time frame since B starts an hour after A Think A starts 40km from the origin with speed 40km/h And B starts from the origin with speed 50km/h Hence D (A)= 40 + 40t D (B) = 50t Hence using the cosine rule D^2 = D (A)^2 +D(B)^2 - 2D(A)×D(B)×cos (60) = 1600 + 3200t + 1600t^2 +...

I will post the answer soon

You have to use consine rule to find the distance in terms of t and differentiate that

My bad i didnt read that also the fact that the positive and negative sign does get lost sorry X_X Do you think this kind of question will come out in any exams?

true asianese this question is just a joke

if there is another way of doing it please post although i am pretty sure that this is the best and fastest method. Trust me you will NEVER NEVER get this question in any test Reason :1. too fu***** long 2. at least 3 pages of working If it does come out, i will kill myself unless the...

Now constant = - (a+1/a)(b+1/b)(y+1/y) = - (aby + ab/y + ay/b + by/a + a/by + b/ay + y/ab + 1/aby) quite long X_X = -(-2 + -1/2 + (a^2b^2 + ......) now i give up typing if you re doing 4 unit you should know what to do from this step onwards keep simplifying and you get 4 hence...

=x^3 + 3x + 2 = 0 has roots a, b, y therefore 1. a + b + y = 0 2. ab + ay + by = 3 3. aby = -2 Now using these identities For the new equation coefficient of x^2 is -(a + b + y + 1/a + 1/b + 1/y) using simple algebra = 3/2 coefficient of X this part is just crazy long = (a + 1/a)(b +...

asianese your method is not quite right i will tell you the right answer in approx 5 minutes

haha very good thats why you never fuck with me omed i

OK i am not trying to be offensive or anything let's just look at these numbers with these marks, you re looking around 60~70ish atar mark (may be lower) assuming the numbers next to each subject are representing raw marks People say they can improve and they are going to do better in trials...

I agree I came first in my 4unit and 3unit but i screwed up my chem and englished exams :)

let g(x) = ln(x)^2 g'(x) = 2(ln(x))/x f(x)= x F(x) = 1/2x^2 integrating by parts Integral(xln(x)^2) = 1/2x^2 * ln(x)^2 - Integral (xln(x)^2) 2Integral(xln(x)^2) = 1/2x^2 * ln(x)^2 Integral(xln(x)^2) = 1/4x^2 *ln(x)^2

haha funny omed i just went to your thread in atar guidance section you are a joke what is your mental age 5? good luck for your med interview with your bs

do you thibk our year's Mx1 will get much more harder compared to the last one

i meant for MX1 not MX2

thanks i will aim for 69 i cant get 70 always make silly mistakes

for MX1 what was your raw mark

thanks to other members for your answers and you can fuck yourself omed this is not fucking conpetition where you kill each other to come first calm down if you state 1 good for you no need to fucking shit with other people who just want to study math and enjoy hsc

hey what do you think i need to get in the hsc exam to get hsc mark of above 98 for both MX1and MX2 the raw marks /70 and /100 one quick question if you're first in school it doesnt matter what your assessment marks are right? i am confused on this can someone briefly outline the...