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they give the same thing

Re: 回复: Re: integration what's the derivative of sin-1x?

from a few lines in: \int \frac{sin^2x - cos^2x}{sin^3xcosx}dx\\ \int \frac{1}{sinxcosx} - \frac{cosx}{sin^3x}dx\\ \int \frac{sin^2 + cos^2x}{sinxcosx} - cosxsin^{-3}x dx\\ \int \frac{sinx}{cosx} + \frac{cosx}{sinx} - cosxsin^{-3}x{sinx}dx\\ = -ln|cosx| + ln|sinx| + \frac{1}{2}sin^{-2}x\\ =...

calculate the pH for each concentration as if the acid were strong and monoprotic. the one with a more acidic pH than what you calculated must be able to donate more than one

but you still have the same arrangement are you disagreeing with the answer of 12!/(5!*2!) ?

order 12 letters = 12! but the letters from koala have to be kept in a specific order, so divide by 5! then divide by 2! due to two e's = 12!/5!2!

definitely an overestimate for english. probably a bit high for science as well of course, it's too early to tell just yet. depends how much work i end up putting in

beethoven

lol i'm not gonna get too high a UAI. i only get really good marks in maths, fairly good in phys/chem but not great, and average in english. i'm expecting/hoping for ~95

use log law and the t identities also, the integral of secx can be made into a standard integral if you let u=secx

k

the derivative of ex is ex any other base, a, and you get a constant, ln[a], out the front, so using base e allows us to more easily differentiate and integrate

finding I about centre; \int r^2 dm\\ dm = 2\pi \rho r.dr\\ 2\pi \rho\int_{a}^{b}r^3 dr\\ \pi \rho(b^4 - a^4)/2 the I about just the x-axis will just be half of this. how come it's perfectly fine to ask for help and how to answer a question in the hsc forums, but not in the uni ones..? (yeah...

just replace all the n's with (n+1)../ or k with (k+1) whatever

pentex sux! pentex sux! they drain the lifeforce of my tribe. pentex sux! . if i had my way. IF I HAD MY WAY i'd render them all ripped and torn ALL THAT SUX DIES . dun dun. dududundun. duuuh

the derivative of the function is 3x2 - 4x + 2 = 3(x - 2/3)2 + 2/3 > 0 for all x graph is monotonic increasing .'. an inverse exists to sketch just find intercepts, point of inflexion etc. edit: question was already answered in other thread

sin3x = sinx(1-cos2x) ..

sums to products just means you break sin5a and sin3a into sin(4a + a) and sin(4a - a) you could also use sin8Asin2A = sin(5a + 3a)sin(5a - 3a)

it's squared. the angle for maximum height would be straight up, ie. 90' it just comes from v2 - u2 = 2as (setting v=0)

just listened to fighting starlight. quite nice