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Is there even enough periods in the fortnight to do 15 units? I would probably say to drop french - especially if you don't always have a teacher (what's OHS exactly?); you can always just teach yourself some basic french when you're in the mood. You might as well keep music 1, at least for a...

"Solve cotA +4tanA =4cosecA for 0=<360" fixed it

you could always just drop them both (even 13 units is quite a lot) do you really learn much in either of them? are you going better in either of them than in any of your other subjects that you don't want to drop?

haha I didn't even notice that. that would've made it a lot simpler.

I've got no more school

sin[x] - rt3cos[x] = 2sin[x - pi/3] = 0 when x = pi/3, 4pi/3 etc. so sin[x] - rt3cos[x] is always positive between those limits, which is why the single integral gives you the area I'm pretty sure that as long as the area between the 2 curves is in the one section (ie they don't intersect...

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you use it if you have a given number of moles in a substance, and you want to find the concentration after adding some amount of water etc., or the required volume to give a certain concentration the reasoning for it is: concentration = number of moles per unit volume (definition) C1 = n1/V1...

i get 78.32 to 2 dp but I think my working has mistakes in it can you please confirm ??? ??? ??? :) :) :( :) :)

nCr = (n-1)C(r-1) + (n-1)Cr = (n-1)C(r-1) + (n-2)C(r-1) + (n-2)Cr = ... = Sum[1 < a < n-r+1] (n-a)C(r-1) in the bracketed section, [(1+x)n-1 +...], the coefficient of any given (r-1)th power of x is Sum[1 < a < n-r+1] (n-a)C(r-1) = nCr but this term is then multiplied by x, which adds 1 to the...

what do you mean? touches = tangent, intersect = passes through (might include tangent as well)

Some questions I have (you don't need to answer them separately, or in great detail, or anything, and a couple of them have probably been answered already - I haven't read the whole thread, and find it a bit hard to read through the quoted sections, and other parts with political terminology)...

yeah I'd say that's it. you could also take the negative square root. The square root is defined to be positive, but the indice law you're using is then only true for numbers >0

you can do it easily by writing as sinx/cos2 quite easily if you just do it by inspection (like tommykins did) you can see that ∫sinx.sec2 = ∫sinx.cos-2x = (cos[x])-1 and then just evaluate that if you're doing a definite integral, is it usually easier to substitute in the limits in terms of...

http://en.wikipedia.org/wiki/Euler%27s_formula#Proofs how hard were you looking? =/

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would the answer be -5/7 x + 45/7 ?

this one would be easier/less messy to solve if you evaluate 1/x first 1/(√6-3) * (√6+3)/(√6+3) = (√6+3)/(6-32 = -(√6+3)/3 x - 1/x = (3√6-9)/3 - -(√6+3)/3 = (3√6 + √6 - 9 + 3)/3 = (4√6 - 6)/3 = 2(2√6 -3)/3 or 4/3 √6 - 2 [second looks simpler imo, but first is probably the simplest form. not...