I know they've already been answered, but..
1. where r is the diagonal distance;
r2 = x2 + 602
2r.dr = 2x.dx
dr/dx = x/r
and dx/dt = 8
when r = 100, x = 80, so x/r = 4/5
dr/dx.dx/dt = dr/dt = 4/5 *8 = 6.4
2. dX/dt = 3, dY/dt = 4
R2 = X2 + Y2
2R.dR = 2X.dX + 2Y.dY
after 2 hours, the Y distance...