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tan120 = -rt3 P = (0,a) and (2-a)/-2rt3 = tan120 = -rt3 2 - a = 6 a = -4 P = (0, -4) the circle containing (7,6) and (8,-2) as a diameter (any point C, other than A or B, on the circle has condition that ACperpBC since the triangle formed at the diamater is a right triangle) has the equation...

1. 1/8 chance of no heads - so 7 ways of getting at least 1 head 1 way of getting 3 heads, so a 1/7 probability 2. 70% is not diseased, so .5*70% = 35/100 will be poorer than average but not diseased 30% is diseased, so .8*30% = 24/100 will be poorer than average and diseased so if a harvest is...

Im+1 = S[1,0] xm+1ex (can you do that? as in assuming that is what Im+1 is equal to) = [1,0]xm+1ex - (m+1)*S[1,0]xmex = e - (m+1)Im you didn't sub in m+1 in mI(m-1) properly. It should be (m+1)I(m)

can't wait to do 4U

< CSP = < RSQ (vert. opp) < SCP = < RAP (exterior of opp side of cyclic quad) < RPA = < DPR (given) .'. RPA ||| SCP with < ARP = < CSP = <QSR = <QRS < QRY = QSY (given) so < QYR = < QYS = 90' (angle sum of triangle, QYR+QYS = 180) .'. QY is perpendicular to RP

what's that got to do with trig formulae? (3x+2)(2x +1+rt7)(2x+1-rt7)/2

Dissolution is the process of the ions separating. It can be referred to as 'solvation' but not as 'solution'. Solution means the mixture of the ions/whatever else and the water/whatever else.

distance, D, from P to a certain point = 180tan[x], where x is the angle between the ray of light and the line drawn from L to P The light has a period of 10 seconds (goes 2pi in 10s) so dx/dt = pi/5 dt/dx = 5/pi D=180tan[x] x = arctan[D/180] dx/dD = 1/(180 + D2/180) dD/dt = (180 + D2/180)pi/5...

wouldn't P(2C's together) = 7!/2! ?

it's 20 installments not 20 years ^ my working was: A = 500,000 I = (1 + 0.12/12)^6 n = installments AI^20 - nI^19 - ... n = 0 (nI^20 - n)/(I-1) = AI^20 n = AI^20(I-1)/(I^20-1) then plug in values

I got $44131. Did you enter it wrongly into excel, or have I made a mistake? Also, wouldn't the interest rate be (1.01)6, as opposed to (1.01)12/2 ? actually, I think this bit would be wrong "Then use the normal normal forumula, using 0.1268250 as the annual rate and just dividing it by 2."

sin3x/2x = (3/2)sin3x/3x lim (sin3x / 2x) = 3/2

a way you could approach it, apart from using trig substitution would be to observe that the function is a semicircle, then find an expression for the definite integral (area of that segment the circle) from 0 to some value, b. Then just add a constant.

I got the same answer (basically) and wolfram gives it exactly as you have it http://integrals.wolfram.com/index.jsp?expr=%2825-x%5E2%29%5E%281%2F2%29&random=false

what was wrong with his answer?

10 across top and bottom, 8 across the sides. Total = 36 (in general, for a square board of sides n it will be 4(n-1), for a rectangle with sides m and n it will be 2(n-1) + 2(m-1) -> for m and n >1) not sure what '2 different solutions means though'. How can there be more than 1?

ah yeah, that method didn't actually work.. originally what I had was: pi/4 Int 2,0 [4 - y2] - pi Int 1,0 [1 - y2] pi/4 (8 - 8/3) - pi + pi/3 = 2pi/3 I had gotten the 3/4 y2 from subtracting 1 - y2 from 1 - y2/4

concurrent means the lines pass through a single point - one line passes through the point of intersection of the other 2

what are good degrees, and unis, for majoring in mathematics?

for b) you have y=2sqrt(1-x^2) and y= sqrt(1-x^2) so x2=1 - y2/4 and x2 = 1 - y2 you're finding the volume between y=0->2 (since 2 is the maximum y value of the 2 functions) so pi Int 2,0 [3/4 y2.dy] = pi[1/4 y3.dy]2,0 = 2/3pi sounds about right to me. (you'll notice that the two graphs are...