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Re: The Official Tennis Thread Henri Leconte's annoying. Anyways, i think Murray will win the Aus Open this year

Both are just textbook cram subjects. But as above has stated, flick through a couple of phys and chem books and see what you like in either subject

Stay with MX1. I achieved a mid-low band 5 (i think 84 or 82) in SC and averaged 50%-60% for MX1 in year 11 where my lowest ark was 12.5% (lol). But i stuck with it. Things ended up clicking in yr12, even though i didn't do that much maths. I eventually got mid E4's for both maths.

Hi, I'm still in the enrolling process. Idk what to take but we have till 26th February, so it's not a big rush.

Oscillating functions can cause problems when using Newton's method.

His methods a lot better than long division and more efficient when one gets used to the equating co-effs poly method.

Yeah, nw. Fancy solving my question? It's pretty easy if you have seen the hint. Otherwise, it's pretty difficult

I've just made up a question. it's quite easy though. a) Prove by induction or otherwise: [a1+a2+...+an]/n > (a1a2...an)^(1/n) b) Hence or otherwise, prove that (1-e)^-n=n^n.e^(n/2)(1-n) for n large where n E Z+ HINT: Replace a1,a2,...,an by 1,e,e^2,...,e^n

I think both ways are correct. @addikaye03: That's a pretty good solution

Yeah, sorry. It was pretty late and my concentration levels were pretty low. Thanks

Let n=1: S {x=inf to x=0} e^-x dx = -[e^-(inf)-1] = -(0-1) = 1 =0! Let n=k: Assume, S {x=inf to x=0} x^(k-1).e^-x dx=(k-1)! Let n=k+1: S {x=inf to x=0} x^(k).e^-x dx = -[e^-x.x^k] {x=inf to x=0} - k.S {x=inf to x=0} x^(k-1).e^-x dx = -(0-0)+k(k-1)! [As e^x dominates x^k] = k!

Ok. Can't say i did the extension questions in yr12 as i didn't do any homework for 3u in yr 12.

Yeah, sorry. I don't think it works though.

lol haha. This is coming from the guy that told ppl to study for non-uniform circular motion. Yeah, in the extension questions and some intermediate questions of Cambridge yr11 and 12. The author introduces power series and other uni topics which aren't ever studied in high school.

I got it out like this, but i'm wondering whether a polynomial proof is possible. The polynomial is degree 3 with roots tan(A/2), tan(B/2), tan(C/2) and sum of roots=product of roots.

They're angles in a triangle.

Re: The Official Tennis Thread I think Andy Murray potentially can win Aus Open and a few other slams this year.

a) S {for a to 0} x^2 dx =a^3/3 2/3. Area AOP=2/3.1/2.(a^2)(a) =1/3.a^3 =a^3/3 b) S {for a to -a} x^2 dx =2a^3/3 1/3.Area ABQP=a^2.2a =2a^3*1/3 =2/3.a^3 =2a^3/3

Everyone says Com/Law is the best

Last time i checked, there were very few current MX2 students actually posting on this thread. Anymore questions?