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But water in = water out... Do they let you go to the toilet for a 3 hour exam :S

Umm, yes it does -- You're wrong and SuccessOne is correct, as usual.

t=2.88 years = 2 years + 0.88 of a year. 0.88 *12 = 10.56 , which is the 11th month. So it occurs in 11th month of the third year. There is logic behind it it too. As I said if it takes 34.56 months to occur, then it occurs in the 35th month. Say for instance, that it takes t=0.1 month(s)...

Uhh, t=2.88 years means that it occurs in the 3rd year. Towards the end of the 3rd year actually. ie. in November (11th month) in the 3rd year. This is exactly what I was getting at in my previous post... Did you read it? -_-;

That's in series. I haven't encountered such an example in Applications of Calculus to the Physical world. However for instance, if you have t=22.18 years, this would occur in the 23rd year. Something you need to be aware of if the question asks it.

You should put it. They may decide to dock you for not putting it any single year. It's like general solutions. You should put that 'n is any integer', but I'm sure that not many people don't and get away with it. Of course the correct answer would be to put it.

The mantra, ie. "It is true for n=1, so it is true for n=1+1=2. It is true for n=2, so it is true for n=2+1=3 and so on for all positive integral values of n" seems to be the 'old fashioned' way of concluding mathematical induction. I wonder where it actually came from?

Here's the thing I read: The concluding statements for inductions provided by many candidates show that they incorrectly think that a proof by induction is actually an iterative proof, in which you imagine that the recipe should be repeated as many times as necessary in order to verify the...

You were taught for the 'conclusion' of Step 2 to be "If it is true for n=k, so it is true for n=k+1" and for Step 3 "It is true for n=1 so it is true for n=1+1=2. It is true for n=2 so it is true for n=2+1=3 and so on for all positive integral values of n". From what I have read in the HSC, it...

You do realise that it takes ALOT of time to write up solutions nicely, dont you? I have them for Binomial, combinations and binomial probability and applications of calculus to the physical world. But I'm not keen on sharing them here =\ maybe privately, but then again, it is copyright...

The top mark for that paper was 80% at SGS.

You need to show that 3k+1 > (k+1)(k+2)(k+3). This is proving that it is true for n=k+1.

=\ That's not very smart... Umm I can send you my lesson notes from class about the std model of matter if you want. McCallum summarises things nicely and give us the stuff that we must know. You're never on MSN btw?

So bally didn't finish it? :O

So it is not undefined. If it's undefined that means the angle=infinity, which is clearly not the case. So it's indeterminable.

Umm... you do know that arg(a+ib) = tan-1(b/a) right?

There are four cases of indeterminable. They are: 0/0 , infinity*0 , infinity - infinity, infinity*0 There is a difference between undefined and indetermineable.

Step \ 1: \ When \ n=5 \ LHS=3^5=243, \ RHS=5(5+1)(5+2)=210 \\ \therefore LHS > RHS \\ \therefore \text{It is true for n=5}. \\ Step \ 2 : \text{Assume it is true for n=k} \ (k \le n, \ k \epsilon J^+) \ \text{and prove it is true for n=k+1} \\ ie. \ 3^k>k(k+1)(k+2) \ -(1) \\ If \ n=k+1 \ 3^n =...

No ==> Indeterminable. Undefined is something like 2/0...

Re: Ext 2 Past Papers + Answers Have you even done them? :S