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  1. bleakarcher

    Year 12 2012 Chit Chat Thread

    Dude send it to me too?
  2. bleakarcher

    Year 12 2012 Chit Chat Thread

    I didn't find it that difficult tbh, I was quite surprised when people told me they had only had a go at 31/70 marks.
  3. bleakarcher

    Year 12 2012 Chit Chat Thread

    I'll upload my 3U paper when I get it btw for the guys that want to see it.
  4. bleakarcher

    Year 12 2012 Chit Chat Thread

    I was trying not to laugh.
  5. bleakarcher

    Year 12 2012 Chit Chat Thread

    lol'd at how it goes from 100 to 80 to 70 to fail.
  6. bleakarcher

    Year 12 2012 Chit Chat Thread

    oh lol. My paper was on prelim 3U.
  7. bleakarcher

    Year 12 2012 Chit Chat Thread

    I think I did this paper. Was the last question 3D trigonometry?
  8. bleakarcher

    Year 12 2012 Chit Chat Thread

    Thanks sean. It's not that epic though tbh. It's prelim 3U lol.
  9. bleakarcher

    Year 12 2012 Chit Chat Thread

    Thanks guys. I knew I was going to be an outlier in terms of the marks when I walked out of the exam room to see people so angry they smashed their liquid papers on the floor with all their strength.
  10. bleakarcher

    Year 12 2012 Chit Chat Thread

    Got 96% in my 3U yearly. Doubled the 2nd highest mark lol (47%).
  11. bleakarcher

    Preliminary 3U Paper - Realise Edition

    Thanks for taking the time to make this bro.
  12. bleakarcher

    Year 12 2013 Chit Chat Thread

    Re: Year 11 2012 Chit Chat Thread gtfo.
  13. bleakarcher

    Preliminary 2004 CSSA Physics

    You're assuming the total current through both circuits is the same. It isn't though.
  14. bleakarcher

    Preliminary 2004 CSSA Physics

    How so?
  15. bleakarcher

    Preliminary 2004 CSSA Physics

    I actually got D for part 5. Say all the resistors have a resistance R, since they're identical. In the first circuit, R_T=R+R=2R. So the total current through the resistors is I_1=12/(2R)=6/R. So the current flowing through both resistors is 6/R. In the second circuit, 1/(R_T)=1/R + 1/R=2/R so...
  16. bleakarcher

    Year 12 2012 Chit Chat Thread

    PQ is tangent to x^2=2ay so solve simultaneously x^2=2ay and y=(1/2)[p+q]x-apq to form a quadratic equation and set the discriminant of the quadratic equal to 0.
  17. bleakarcher

    Year 12 2012 Chit Chat Thread

    yeah my teacher uses this technique all the time. I personally don't like because it's very mechanical. You don't really know what your doing either..
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