Argand proofs (1 Viewer)

relativity1

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Wait can i just say for I)since its in the 4th quadrant angle is just -theta?
 
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1) Consider the values of sin and cos around the different quadrants of the unit circle (A-S-T-C) It's obvious that cosθ = cos-θ and sin-θ = sin-θ (for mod arg form, θ should be in the first 2 quadrants)

2) sin (pi/2-θ)= cos θ and similarly, cos (pi/2-θ) = sin θ (sum and difference of two angles)
 
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