Electrostatics question (1 Viewer)

[erucibon]

Calculate electric field strength due to the 4μ C charge at the position of the other charge

Thanks

 

[Pedro123]

By Coloumb's law: (Apologies I cannot write equations)
The force felt would be (Coloumb's Constant*absolute value(Charge 1 * Charge 2))/distance^2
Coloumb's constant is about 8.987*10^9 (Units of NM^2C^-2
Subbing in, we get a value of about 7.99x10^11 newtons

 

[jazz519]

By Coloumb's law: (Apologies I cannot write equations)
The force felt would be (Coloumb's Constant*absolute value(Charge 1 * Charge 2))/distance^2
Coloumb's constant is about 8.987*10^9 (Units of NM^2C^-2
Subbing in, we get a value of about 7.99x10^11 newtons

It's asking for the electric field strength rather than the force between the particles

So you need to use that formula but without the other charge (so E = kq1/r^2)

 

[Drdusk]

Yeah