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General Thoughts: Mathematics (1 Viewer)

jordiviv

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Jan 11, 2011
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Does anybody know of any solutions posted online as of yet?
...or when some might be released?
:)
 

kliro_10

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nahh you had to start off saying that 0<Q<2pi and then sub in the value for Q that you found in part (i) and rearrange by splitting up the inequality and solving, then bringing it back together
 

forkandspoon

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Does anyone know the ratio of the volume of the cylinder to the volume to the paraboloid?
 

jgalpin

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No it wasn't....... it was a geometric series not limiting sum, answer came out to be around 23.98
 

forkandspoon

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i got pi h^3 / 3 coz u had to intergrate c^2
Huh? why? What do you think i did wrong? i found the volume about the y axis. so V= (pi) integral of (x^2) dy. But y=x^2 sooo...
Therefore, integral of (y)dy from 0 to h. Therefore, = (pi)(Y^2)/2.. now i subbed in limits: (pi)(h^2)/2.. where did the 'c' come from?
 

umz93

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Thats what I thought, because it was a definite integral!
 

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