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eunkuk91

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can someone tell me the equation for circle is it (a^2+b^2=r^2)? and to find y-asymptote do you just devide everything by the highest factor such as
x^2/x^2+1 = 1 therefore the horizontal asymptote is y=1?
 

independantz

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Eh aren't you in year 12, shouldn't you know the eq of a circle by now?

anyway it's x^2+y^2=r^2

essentially for horizontal asymptotes you take the limit as x approaches plus/minus infinity.
 

AlexJB

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(x-a)^2 + (y-b)^2 = r^2
With centre (a, b)

Think that's it.
 

P.T.F.E

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No asymptotes for a circle, asymptotes are when the y value or x value doesnt exist
 

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