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tutor01

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I am trying to find the integral of dx/(3+4sin(2x)). Can anyone help? Thanks!
 

tutor01

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was hoping for a solution. t=tanx and from there. Is that best? Thanks.
 

pikachu975

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was hoping for a solution. t=tanx and from there. Is that best? Thanks.
I reckon splitting sin2x into 2sinxcosx could work too.

t = tan(x/2)
x = 2tan^-1 (t)
dx = 2dt/(1+t^2)

Integral of 1/(3+8(2t/1+t^2)(1-t^2 /1+t^2)) * 2dt/(1+t^2)

Go from there, just simplify then integrate
 

integral95

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Yes I believe t = tan x would be a better substitution in this integral.
 

integral95

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Wolfram alpha gives an inverse hyperbolic tan function. So have fun.
 

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