You are almost there. If you put x=tan theta, does it look familiar? You've solved that in the previous one.I've reduced the integral to
if someone else wants to finish it from this, but it seems very difficult.
Maybe a different approach might be necessary?
This is a skeleton solution.This is another beast.
*solubleThis is a skeleton solution.
By substituting u=(x-2)/sqrt(2) and considering f(x)+f(-x), the integral can be re-written as
A tangent substitution will turn it into a format that Wolfram can solve...finally
I know Wolfram used hyperbolic tangent substitution but it is also solvable in MX2 by secant substitution.
Alternatively, if you don't mind handling improper integral, you can do some algebraic manipulation to get:
Substituting v=u-1+u and w=u-1-u will lead to two improper (but solvable) integrals because u-1 blows up at 0.
That's correct, but you don't need to graph the function, you just need to know the sign of the thing under the absolutes at every point in the region.I think this is my first "Stupid_girl's Integrals" ill get. Maybe idk
Well didnt get a but got a Thats outta be good right?
I had to graph the thing, is it possible without graphing it?