limiting gas (1 Viewer)

[pasta8]

how do you find the volume of NO2 in this reaction? do i use the moles of NO or O3 if the question tells you that NO weighs 0.66g and O3 weighs 0.72g

NO (g) + O3 (g) --> NO2 (g) + O2 (g)

 

[randomnessss]

NO (g) + O3 (g) --> NO2 (g) + O2 (g)
​

Theoretical mole ratio = 1 : 1 : 1 : 1

n(NO) = 0.66/(16.00 + 1401) = 0.022 moles
n(O3) = 0.72/(16.00 + 16.00 + 16.00) = 0.015 moles

Therefore ozone is the limiting reagent. Since it is the limiting reagent (a chemical which is present in lesser amounts comparatively which prevents a complete reaction), we must use its no. of moles in calculations.

According to the theoretical mole ratio 1 mole of O3 will form 1 mole of NO. Hence:
n(NO2) = 0.015

m(NO2) = 0.015 x (16.00 + 16.00 + 14.01) = 0.6915 g
​