• Want to take part in this year's BoS Trials event for Maths and/or Business Studies?
    Click here for details and register now!
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page

Limits (2 Viewers)

D

danz90

Active Member
Joined
Feb 2, 2007
Messages
1,467
Location
Sydney
Gender
Male
HSC
2008
By using the rule:

lim (sin nx / nx) = 1
how can we manipulate limits so that we can get it in the form above?
e.g. evaluate lim (sin3x / 2x) ..
 
L

lolokay

Active Member
Joined
Mar 21, 2008
Messages
1,015
Gender
Undisclosed
HSC
2009
sin3x/2x = (3/2)sin3x/3x
lim (sin3x / 2x) = 3/2
 
D

danz90

Active Member
Joined
Feb 2, 2007
Messages
1,467
Location
Sydney
Gender
Male
HSC
2008
lolokay said:
sin3x/2x = (3/2)sin3x/3x
lim (sin3x / 2x) = 3/2
Click to expand...
why do u multiply by 3/2 ?
is there a certain procedure when u get this type of question...
 
midifile

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
When you do these quesitons you want the number in front of the x to be the same on the top and the bottom. So becasue you have sin3x on the top you want 3x on the bottom.

To get this you times by 3/2. Then sin3x/3x just equals 1 so then answer is 3/2
 
You must log in or register to reply here.

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top